diff options
author | Amos Kong <akong@redhat.com> | 2013-04-16 13:47:32 +0800 |
---|---|---|
committer | Luiz Capitulino <lcapitulino@redhat.com> | 2013-04-19 08:32:44 -0400 |
commit | 153d02e338a063ad5c51ff0725d5d88285f44121 (patch) | |
tree | edee4728e063520e7562483a6e324087d5e38a50 /ui/input.c | |
parent | 09dada400328d75daf79e3eca1e48e024fec148d (diff) |
monitor: fix the wrong order of releasing keys
(qemu) sendkey ctrl_r-scroll_lock-scroll_lock
Executing this command could not let Windows guest panic, it caused by
the wrong order of releasing keys. This problem was introduced by
commit e4c8f004c55d9da3eae3e14df740238bf805b5d6.
The right release order should be starting from last item.
Signed-off-by: Amos Kong <akong@redhat.com>
Signed-off-by: Luiz Capitulino <lcapitulino@redhat.com>
Diffstat (limited to 'ui/input.c')
-rw-r--r-- | ui/input.c | 8 |
1 files changed, 3 insertions, 5 deletions
diff --git a/ui/input.c b/ui/input.c index 9abef0cd78..ecfeb43824 100644 --- a/ui/input.c +++ b/ui/input.c @@ -234,13 +234,11 @@ static void free_keycodes(void) static void release_keys(void *opaque) { - int i; - - for (i = 0; i < keycodes_size; i++) { - if (keycodes[i] & 0x80) { + while (keycodes_size > 0) { + if (keycodes[--keycodes_size] & 0x80) { kbd_put_keycode(0xe0); } - kbd_put_keycode(keycodes[i]| 0x80); + kbd_put_keycode(keycodes[keycodes_size] | 0x80); } free_keycodes(); |