Don't sync dirty bitmaps in postcopy

Once we're in postcopy the source processors are stopped and memory
shouldn't change any more, so there's no need to look at the dirty
map.

There are two notes to this:
  1) If we do resync and a page had changed then the page would get
     sent again, which the destination wouldn't allow (since it might
     have also modified the page)
  2) Before disabling this I'd seen very rare cases where a page had been
     marked dirtied although the memory contents are apparently identical

Signed-off-by: Dr. David Alan Gilbert <dgilbert@redhat.com>
Reviewed-by: David Gibson <david@gibson.dropbear.id.au>
Reviewed-by: Juan Quintela <quintela@redhat.com>
Reviewed-by: Amit Shah <amit.shah@redhat.com>
Signed-off-by: Juan Quintela <quintela@redhat.com>

1 files changed, 5 insertions, 2 deletions

diff --git a/migration/ram.c b/migration/ram.c
index 8bf0841fad..339b001daf 100644
--- a/migration/ram.c
+++ b/migration/ram.c
@@ -1846,7 +1846,9 @@ static int ram_save_complete(QEMUFile *f, void *opaque)
 {
     rcu_read_lock();
 
-    migration_bitmap_sync();
+    if (!migration_in_postcopy(migrate_get_current())) {
+        migration_bitmap_sync();
+    }
 
     ram_control_before_iterate(f, RAM_CONTROL_FINISH);
 
@@ -1881,7 +1883,8 @@ static void ram_save_pending(QEMUFile *f, void *opaque, uint64_t max_size,
 
     remaining_size = ram_save_remaining() * TARGET_PAGE_SIZE;
 
-    if (remaining_size < max_size) {
+    if (!migration_in_postcopy(migrate_get_current()) &&
+        remaining_size < max_size) {
         qemu_mutex_lock_iothread();
         rcu_read_lock();
         migration_bitmap_sync();