exec: remove ram_addr argument from qemu_ram_block_from_host

Of the two callers, one does not use it, and the other can compute
it itself based on the other output argument (offset) and the RAMBlock.

Reviewed-by: Marc-André Lureau <marcandre.lureau@gmail.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/include/exec/cpu-common.h b/include/exec/cpu-common.h
index a2c3b92742..fc609ade02 100644
--- a/include/exec/cpu-common.h
+++ b/include/exec/cpu-common.h
@@ -60,7 +60,7 @@ void qemu_ram_remap(ram_addr_t addr, ram_addr_t length);
 MemoryRegion *qemu_ram_addr_from_host(void *ptr, ram_addr_t *ram_addr);
 RAMBlock *qemu_ram_block_by_name(const char *name);
 RAMBlock *qemu_ram_block_from_host(void *ptr, bool round_offset,
-                                   ram_addr_t *ram_addr, ram_addr_t *offset);
+                                   ram_addr_t *offset);
 void qemu_ram_set_idstr(RAMBlock *block, const char *name, DeviceState *dev);
 void qemu_ram_unset_idstr(RAMBlock *block);
 const char *qemu_ram_get_idstr(RAMBlock *rb);