diff options
| author | Paolo Bonzini <pbonzini@redhat.com> | 2019-01-23 14:56:04 +0800 |
|---|---|---|
| committer | Paolo Bonzini <pbonzini@redhat.com> | 2019-03-07 21:45:53 +0100 |
| commit | 7c28b925b7e176b4e44ed05d23cf883561000546 (patch) | |
| tree | f4f502446ce568b0b7e0b2d8296dc1120445fa82 /default-configs/hppa-softmmu.mak | |
| parent | e9947d18df97e6c6584f020cf9cc995404cc8061 (diff) | |
build: convert pci.mak to Kconfig
Instead of including the same list of devices for each target,
set CONFIG_PCI to true, and make the devices default to present
whenever PCI is available. However, s390x does not want all the
PCI devices, so there is a separate symbol to enable them.
Done mostly with the following script:
while read i; do
i=${i%=y}; i=${i#CONFIG_}
sed -i -e'/^config '$i'$/!b' -en \
-e'a\' -e' default y if PCI_DEVICES\' -e' depends on PCI' \
`grep -lw $i hw/*/Kconfig`
done < default-configs/pci.mak
followed by replacing a few "depends on" clauses with "select"
whenever the symbol is not really related to PCI.
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
Signed-off-by: Yang Zhong <yang.zhong@intel.com>
Cc: Michael S. Tsirkin <mst@redhat.com>
Reviewed-by: Thomas Huth <thuth@redhat.com>
Message-Id: <20190123065618.3520-31-yang.zhong@intel.com>
Acked-by: Richard Henderson <richard.henderson@linaro.org>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
Diffstat (limited to 'default-configs/hppa-softmmu.mak')
| -rw-r--r-- | default-configs/hppa-softmmu.mak | 5 |
1 files changed, 4 insertions, 1 deletions
diff --git a/default-configs/hppa-softmmu.mak b/default-configs/hppa-softmmu.mak index e0a6cdcad1..85a201184a 100644 --- a/default-configs/hppa-softmmu.mak +++ b/default-configs/hppa-softmmu.mak @@ -1,5 +1,6 @@ -include pci.mak include usb.mak +CONFIG_PCI=y +CONFIG_PCI_DEVICES=y CONFIG_SERIAL=y CONFIG_SERIAL_ISA=y CONFIG_ISA_BUS=y @@ -7,6 +8,8 @@ CONFIG_I8259=y CONFIG_E1000_PCI=y CONFIG_IDE_CMD646=y # CONFIG_IDE_MMIO=y +CONFIG_SCSI=y +CONFIG_LSI_SCSI_PCI=y CONFIG_VIRTIO_VGA=y CONFIG_MC146818RTC=y CONFIG_DINO=y |