softfloat: do not set denominator high bit for floatx80 remainder

The floatx80 remainder implementation unnecessarily sets the high bit
of bSig explicitly.  By that point in the function, arguments that are
invalid, zero, infinity or NaN have already been handled and
subnormals have been through normalizeFloatx80Subnormal, so the high
bit will already be set.  Remove the unnecessary code.

Signed-off-by: Joseph Myers <joseph@codesourcery.com>
Reviewed-by: Richard Henderson <richard.henderson@linaro.org>
Message-Id: <alpine.DEB.2.21.2006081656220.23637@digraph.polyomino.org.uk>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>

1 files changed, 0 insertions, 1 deletions

diff --git a/fpu/softfloat.c b/fpu/softfloat.c
index ab50088c35..1ee3342715 100644
--- a/fpu/softfloat.c
+++ b/fpu/softfloat.c
@@ -5751,7 +5751,6 @@ floatx80 floatx80_modrem(floatx80 a, floatx80 b, bool mod,
         if ( aSig0 == 0 ) return a;
         normalizeFloatx80Subnormal( aSig0, &aExp, &aSig0 );
     }
-    bSig |= UINT64_C(0x8000000000000000);
     zSign = aSign;
     expDiff = aExp - bExp;
     aSig1 = 0;