1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
|
#!/usr/bin/env python3
# Copyright (c) 2014-2016 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
"""Test mempool re-org scenarios.
Test re-org scenarios with a mempool that contains transactions
that spend (directly or indirectly) coinbase transactions.
"""
from test_framework.test_framework import BitcoinTestFramework
from test_framework.util import *
# Create one-input, one-output, no-fee transaction:
class MempoolCoinbaseTest(BitcoinTestFramework):
def __init__(self):
super().__init__()
self.num_nodes = 2
self.setup_clean_chain = False
alert_filename = None # Set by setup_network
def setup_network(self):
args = ["-checkmempool"]
self.nodes = []
self.nodes.append(start_node(0, self.options.tmpdir, args))
self.nodes.append(start_node(1, self.options.tmpdir, args))
connect_nodes(self.nodes[1], 0)
self.is_network_split = False
self.sync_all()
def run_test(self):
# Start with a 200 block chain
assert_equal(self.nodes[0].getblockcount(), 200)
# Mine four blocks. After this, nodes[0] blocks
# 101, 102, and 103 are spend-able.
new_blocks = self.nodes[1].generate(4)
self.sync_all()
node0_address = self.nodes[0].getnewaddress()
node1_address = self.nodes[1].getnewaddress()
# Three scenarios for re-orging coinbase spends in the memory pool:
# 1. Direct coinbase spend : spend_101
# 2. Indirect (coinbase spend in chain, child in mempool) : spend_102 and spend_102_1
# 3. Indirect (coinbase and child both in chain) : spend_103 and spend_103_1
# Use invalidatblock to make all of the above coinbase spends invalid (immature coinbase),
# and make sure the mempool code behaves correctly.
b = [ self.nodes[0].getblockhash(n) for n in range(101, 105) ]
coinbase_txids = [ self.nodes[0].getblock(h)['tx'][0] for h in b ]
spend_101_raw = create_tx(self.nodes[0], coinbase_txids[1], node1_address, 49.99)
spend_102_raw = create_tx(self.nodes[0], coinbase_txids[2], node0_address, 49.99)
spend_103_raw = create_tx(self.nodes[0], coinbase_txids[3], node0_address, 49.99)
# Create a transaction which is time-locked to two blocks in the future
timelock_tx = self.nodes[0].createrawtransaction([{"txid": coinbase_txids[0], "vout": 0}], {node0_address: 49.99})
# Set the time lock
timelock_tx = timelock_tx.replace("ffffffff", "11111191", 1)
timelock_tx = timelock_tx[:-8] + hex(self.nodes[0].getblockcount() + 2)[2:] + "000000"
timelock_tx = self.nodes[0].signrawtransaction(timelock_tx)["hex"]
# This will raise an exception because the timelock transaction is too immature to spend
assert_raises_jsonrpc(-26, "non-final", self.nodes[0].sendrawtransaction, timelock_tx)
# Broadcast and mine spend_102 and 103:
spend_102_id = self.nodes[0].sendrawtransaction(spend_102_raw)
spend_103_id = self.nodes[0].sendrawtransaction(spend_103_raw)
self.nodes[0].generate(1)
# Time-locked transaction is still too immature to spend
assert_raises_jsonrpc(-26,'non-final', self.nodes[0].sendrawtransaction, timelock_tx)
# Create 102_1 and 103_1:
spend_102_1_raw = create_tx(self.nodes[0], spend_102_id, node1_address, 49.98)
spend_103_1_raw = create_tx(self.nodes[0], spend_103_id, node1_address, 49.98)
# Broadcast and mine 103_1:
spend_103_1_id = self.nodes[0].sendrawtransaction(spend_103_1_raw)
last_block = self.nodes[0].generate(1)
# Time-locked transaction can now be spent
timelock_tx_id = self.nodes[0].sendrawtransaction(timelock_tx)
# ... now put spend_101 and spend_102_1 in memory pools:
spend_101_id = self.nodes[0].sendrawtransaction(spend_101_raw)
spend_102_1_id = self.nodes[0].sendrawtransaction(spend_102_1_raw)
self.sync_all()
assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, timelock_tx_id})
for node in self.nodes:
node.invalidateblock(last_block[0])
# Time-locked transaction is now too immature and has been removed from the mempool
# spend_103_1 has been re-orged out of the chain and is back in the mempool
assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, spend_103_1_id})
# Use invalidateblock to re-org back and make all those coinbase spends
# immature/invalid:
for node in self.nodes:
node.invalidateblock(new_blocks[0])
self.sync_all()
# mempool should be empty.
assert_equal(set(self.nodes[0].getrawmempool()), set())
if __name__ == '__main__':
MempoolCoinbaseTest().main()
|
