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#!/usr/bin/env python3
# Copyright (c) 2018 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
"""Test wallet group functionality."""
from test_framework.test_framework import BitcoinTestFramework
from test_framework.messages import CTransaction, FromHex, ToHex
from test_framework.util import (
assert_equal,
)
def assert_approx(v, vexp, vspan=0.00001):
if v < vexp - vspan:
raise AssertionError("%s < [%s..%s]" % (str(v), str(vexp - vspan), str(vexp + vspan)))
if v > vexp + vspan:
raise AssertionError("%s > [%s..%s]" % (str(v), str(vexp - vspan), str(vexp + vspan)))
class WalletGroupTest(BitcoinTestFramework):
def set_test_params(self):
self.setup_clean_chain = True
self.num_nodes = 3
self.extra_args = [[], [], ['-avoidpartialspends']]
self.rpc_timewait = 120
def run_test (self):
# Mine some coins
self.nodes[0].generate(110)
# Get some addresses from the two nodes
addr1 = [self.nodes[1].getnewaddress() for i in range(3)]
addr2 = [self.nodes[2].getnewaddress() for i in range(3)]
addrs = addr1 + addr2
# Send 1 + 0.5 coin to each address
[self.nodes[0].sendtoaddress(addr, 1.0) for addr in addrs]
[self.nodes[0].sendtoaddress(addr, 0.5) for addr in addrs]
self.nodes[0].generate(1)
self.sync_all()
# For each node, send 0.2 coins back to 0;
# - node[1] should pick one 0.5 UTXO and leave the rest
# - node[2] should pick one (1.0 + 0.5) UTXO group corresponding to a
# given address, and leave the rest
txid1 = self.nodes[1].sendtoaddress(self.nodes[0].getnewaddress(), 0.2)
tx1 = self.nodes[1].getrawtransaction(txid1, True)
# txid1 should have 1 input and 2 outputs
assert_equal(1, len(tx1["vin"]))
assert_equal(2, len(tx1["vout"]))
# one output should be 0.2, the other should be ~0.3
v = [vout["value"] for vout in tx1["vout"]]
v.sort()
assert_approx(v[0], 0.2)
assert_approx(v[1], 0.3, 0.0001)
txid2 = self.nodes[2].sendtoaddress(self.nodes[0].getnewaddress(), 0.2)
tx2 = self.nodes[2].getrawtransaction(txid2, True)
# txid2 should have 2 inputs and 2 outputs
assert_equal(2, len(tx2["vin"]))
assert_equal(2, len(tx2["vout"]))
# one output should be 0.2, the other should be ~1.3
v = [vout["value"] for vout in tx2["vout"]]
v.sort()
assert_approx(v[0], 0.2)
assert_approx(v[1], 1.3, 0.0001)
# Empty out node2's wallet
self.nodes[2].sendtoaddress(address=self.nodes[0].getnewaddress(), amount=self.nodes[2].getbalance(), subtractfeefromamount=True)
self.sync_all()
self.nodes[0].generate(1)
# Fill node2's wallet with 10000 outputs corresponding to the same
# scriptPubKey
for i in range(5):
raw_tx = self.nodes[0].createrawtransaction([{"txid":"0"*64, "vout":0}], [{addr2[0]: 0.05}])
tx = FromHex(CTransaction(), raw_tx)
tx.vin = []
tx.vout = [tx.vout[0]] * 2000
funded_tx = self.nodes[0].fundrawtransaction(ToHex(tx))
signed_tx = self.nodes[0].signrawtransactionwithwallet(funded_tx['hex'])
self.nodes[0].sendrawtransaction(signed_tx['hex'])
self.nodes[0].generate(1)
self.sync_all()
# Check that we can create a transaction that only requires ~100 of our
# utxos, without pulling in all outputs and creating a transaction that
# is way too big.
assert self.nodes[2].sendtoaddress(address=addr2[0], amount=5)
if __name__ == '__main__':
WalletGroupTest().main ()
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