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#!/usr/bin/env python3
# Copyright (c) 2014-2017 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
"""Test descendant package tracking code."""
from test_framework.test_framework import BitcoinTestFramework
from test_framework.util import *
from test_framework.mininode import COIN
MAX_ANCESTORS = 25
MAX_DESCENDANTS = 25
class MempoolPackagesTest(BitcoinTestFramework):
def set_test_params(self):
self.num_nodes = 2
self.extra_args = [["-maxorphantx=1000"], ["-maxorphantx=1000", "-limitancestorcount=5"]]
# Build a transaction that spends parent_txid:vout
# Return amount sent
def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs):
send_value = satoshi_round((value - fee)/num_outputs)
inputs = [ {'txid' : parent_txid, 'vout' : vout} ]
outputs = {}
for i in range(num_outputs):
outputs[node.getnewaddress()] = send_value
rawtx = node.createrawtransaction(inputs, outputs)
signedtx = node.signrawtransaction(rawtx)
txid = node.sendrawtransaction(signedtx['hex'])
fulltx = node.getrawtransaction(txid, 1)
assert(len(fulltx['vout']) == num_outputs) # make sure we didn't generate a change output
return (txid, send_value)
def run_test(self):
''' Mine some blocks and have them mature. '''
self.nodes[0].generate(101)
utxo = self.nodes[0].listunspent(10)
txid = utxo[0]['txid']
vout = utxo[0]['vout']
value = utxo[0]['amount']
fee = Decimal("0.0001")
# MAX_ANCESTORS transactions off a confirmed tx should be fine
chain = []
for i in range(MAX_ANCESTORS):
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, 0, value, fee, 1)
value = sent_value
chain.append(txid)
# Check mempool has MAX_ANCESTORS transactions in it, and descendant
# count and fees should look correct
mempool = self.nodes[0].getrawmempool(True)
assert_equal(len(mempool), MAX_ANCESTORS)
descendant_count = 1
descendant_fees = 0
descendant_size = 0
descendants = []
ancestors = list(chain)
for x in reversed(chain):
# Check that getmempoolentry is consistent with getrawmempool
entry = self.nodes[0].getmempoolentry(x)
assert_equal(entry, mempool[x])
# Check that the descendant calculations are correct
assert_equal(mempool[x]['descendantcount'], descendant_count)
descendant_fees += mempool[x]['fee']
assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee'])
assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN)
descendant_size += mempool[x]['size']
assert_equal(mempool[x]['descendantsize'], descendant_size)
descendant_count += 1
# Check that getmempooldescendants is correct
assert_equal(sorted(descendants), sorted(self.nodes[0].getmempooldescendants(x)))
descendants.append(x)
# Check that getmempoolancestors is correct
ancestors.remove(x)
assert_equal(sorted(ancestors), sorted(self.nodes[0].getmempoolancestors(x)))
# Check that getmempoolancestors/getmempooldescendants correctly handle verbose=true
v_ancestors = self.nodes[0].getmempoolancestors(chain[-1], True)
assert_equal(len(v_ancestors), len(chain)-1)
for x in v_ancestors.keys():
assert_equal(mempool[x], v_ancestors[x])
assert(chain[-1] not in v_ancestors.keys())
v_descendants = self.nodes[0].getmempooldescendants(chain[0], True)
assert_equal(len(v_descendants), len(chain)-1)
for x in v_descendants.keys():
assert_equal(mempool[x], v_descendants[x])
assert(chain[0] not in v_descendants.keys())
# Check that ancestor modified fees includes fee deltas from
# prioritisetransaction
self.nodes[0].prioritisetransaction(txid=chain[0], fee_delta=1000)
mempool = self.nodes[0].getrawmempool(True)
ancestor_fees = 0
for x in chain:
ancestor_fees += mempool[x]['fee']
assert_equal(mempool[x]['ancestorfees'], ancestor_fees * COIN + 1000)
# Undo the prioritisetransaction for later tests
self.nodes[0].prioritisetransaction(txid=chain[0], fee_delta=-1000)
# Check that descendant modified fees includes fee deltas from
# prioritisetransaction
self.nodes[0].prioritisetransaction(txid=chain[-1], fee_delta=1000)
mempool = self.nodes[0].getrawmempool(True)
descendant_fees = 0
for x in reversed(chain):
descendant_fees += mempool[x]['fee']
assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 1000)
# Adding one more transaction on to the chain should fail.
assert_raises_rpc_error(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], txid, vout, value, fee, 1)
# Check that prioritising a tx before it's added to the mempool works
# First clear the mempool by mining a block.
self.nodes[0].generate(1)
sync_blocks(self.nodes)
assert_equal(len(self.nodes[0].getrawmempool()), 0)
# Prioritise a transaction that has been mined, then add it back to the
# mempool by using invalidateblock.
self.nodes[0].prioritisetransaction(txid=chain[-1], fee_delta=2000)
self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
# Keep node1's tip synced with node0
self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
# Now check that the transaction is in the mempool, with the right modified fee
mempool = self.nodes[0].getrawmempool(True)
descendant_fees = 0
for x in reversed(chain):
descendant_fees += mempool[x]['fee']
if (x == chain[-1]):
assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee']+satoshi_round(0.00002))
assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 2000)
# TODO: check that node1's mempool is as expected
# TODO: test ancestor size limits
# Now test descendant chain limits
txid = utxo[1]['txid']
value = utxo[1]['amount']
vout = utxo[1]['vout']
transaction_package = []
# First create one parent tx with 10 children
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 10)
parent_transaction = txid
for i in range(10):
transaction_package.append({'txid': txid, 'vout': i, 'amount': sent_value})
# Sign and send up to MAX_DESCENDANT transactions chained off the parent tx
for i in range(MAX_DESCENDANTS - 1):
utxo = transaction_package.pop(0)
(txid, sent_value) = self.chain_transaction(self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
for j in range(10):
transaction_package.append({'txid': txid, 'vout': j, 'amount': sent_value})
mempool = self.nodes[0].getrawmempool(True)
assert_equal(mempool[parent_transaction]['descendantcount'], MAX_DESCENDANTS)
# Sending one more chained transaction will fail
utxo = transaction_package.pop(0)
assert_raises_rpc_error(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
# TODO: check that node1's mempool is as expected
# TODO: test descendant size limits
# Test reorg handling
# First, the basics:
self.nodes[0].generate(1)
sync_blocks(self.nodes)
self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash())
self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash())
# Now test the case where node1 has a transaction T in its mempool that
# depends on transactions A and B which are in a mined block, and the
# block containing A and B is disconnected, AND B is not accepted back
# into node1's mempool because its ancestor count is too high.
# Create 8 transactions, like so:
# Tx0 -> Tx1 (vout0)
# \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7
#
# Mine them in the next block, then generate a new tx8 that spends
# Tx1 and Tx7, and add to node1's mempool, then disconnect the
# last block.
# Create tx0 with 2 outputs
utxo = self.nodes[0].listunspent()
txid = utxo[0]['txid']
value = utxo[0]['amount']
vout = utxo[0]['vout']
send_value = satoshi_round((value - fee)/2)
inputs = [ {'txid' : txid, 'vout' : vout} ]
outputs = {}
for i in range(2):
outputs[self.nodes[0].getnewaddress()] = send_value
rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
signedtx = self.nodes[0].signrawtransaction(rawtx)
txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
tx0_id = txid
value = send_value
# Create tx1
tx1_id, _ = self.chain_transaction(self.nodes[0], tx0_id, 0, value, fee, 1)
# Create tx2-7
vout = 1
txid = tx0_id
for i in range(6):
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
vout = 0
value = sent_value
# Mine these in a block
self.nodes[0].generate(1)
self.sync_all()
# Now generate tx8, with a big fee
inputs = [ {'txid' : tx1_id, 'vout': 0}, {'txid' : txid, 'vout': 0} ]
outputs = { self.nodes[0].getnewaddress() : send_value + value - 4*fee }
rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
signedtx = self.nodes[0].signrawtransaction(rawtx)
txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
sync_mempools(self.nodes)
# Now try to disconnect the tip on each node...
self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
sync_blocks(self.nodes)
if __name__ == '__main__':
MempoolPackagesTest().main()
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