1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
428
429
430
431
432
433
434
435
436
437
438
439
440
441
442
443
444
445
446
447
448
449
450
451
452
453
454
455
456
457
458
459
460
461
462
463
464
465
466
467
468
469
470
471
472
473
474
475
476
477
478
479
480
481
482
483
484
485
486
487
488
489
490
491
492
493
494
495
496
497
498
499
500
501
502
503
504
505
506
507
508
509
510
511
512
513
514
515
516
517
518
519
520
521
522
523
524
525
526
527
528
529
530
531
532
533
534
535
536
537
538
539
540
541
542
543
544
545
546
547
548
549
550
551
552
553
554
555
556
557
558
559
560
561
562
563
564
565
566
567
568
569
570
571
572
573
574
575
576
577
578
579
580
581
582
583
584
585
586
587
|
#!/usr/bin/env python3
# Copyright (c) 2021 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
from decimal import Decimal
from test_framework.messages import (
COIN,
MAX_BIP125_RBF_SEQUENCE,
)
from test_framework.test_framework import BitcoinTestFramework
from test_framework.mempool_util import fill_mempool
from test_framework.util import (
assert_greater_than_or_equal,
assert_equal,
)
from test_framework.wallet import (
DEFAULT_FEE,
MiniWallet,
)
MAX_REPLACEMENT_CANDIDATES = 100
# Value high enough to cause evictions in each subtest
# for typical cases
DEFAULT_CHILD_FEE = DEFAULT_FEE * 4
class PackageRBFTest(BitcoinTestFramework):
def set_test_params(self):
self.num_nodes = 2
self.setup_clean_chain = True
# Required for fill_mempool()
self.extra_args = [[
"-datacarriersize=100000",
"-maxmempool=5",
]] * self.num_nodes
def assert_mempool_contents(self, expected=None):
"""Assert that all transactions in expected are in the mempool,
and no additional ones exist.
"""
if not expected:
expected = []
mempool = self.nodes[0].getrawmempool(verbose=False)
assert_equal(len(mempool), len(expected))
for tx in expected:
assert tx.rehash() in mempool
def create_simple_package(self, parent_coin, parent_fee=DEFAULT_FEE, child_fee=DEFAULT_CHILD_FEE, heavy_child=False):
"""Create a 1 parent 1 child package using the coin passed in as the parent's input. The
parent has 1 output, used to fund 1 child transaction.
All transactions signal BIP125 replaceability, but nSequence changes based on self.ctr. This
prevents identical txids between packages when the parents spend the same coin and have the
same fee (i.e. 0sat).
returns tuple (hex serialized txns, CTransaction objects)
"""
self.ctr += 1
# Use fee_rate=0 because create_self_transfer will use the default fee_rate value otherwise.
# Passing in fee>0 overrides fee_rate, so this still works for non-zero parent_fee.
parent_result = self.wallet.create_self_transfer(
fee=parent_fee,
utxo_to_spend=parent_coin,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
num_child_outputs = 10 if heavy_child else 1
child_result = self.wallet.create_self_transfer_multi(
utxos_to_spend=[parent_result["new_utxo"]],
num_outputs=num_child_outputs,
fee_per_output=int(child_fee * COIN // num_child_outputs),
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
package_hex = [parent_result["hex"], child_result["hex"]]
package_txns = [parent_result["tx"], child_result["tx"]]
return package_hex, package_txns
def run_test(self):
# Counter used to count the number of times we constructed packages. Since we're constructing parent transactions with the same
# coins (to create conflicts), and perhaps giving them the same fee, we might accidentally just create the same transaction again.
# To prevent this, set nSequences to MAX_BIP125_RBF_SEQUENCE - self.ctr.
self.ctr = 0
self.log.info("Generate blocks to create UTXOs")
self.wallet = MiniWallet(self.nodes[0])
# Make more than enough coins for the sum of all tests,
# otherwise a wallet rescan is needed later
self.generate(self.wallet, 300)
self.coins = self.wallet.get_utxos(mark_as_spent=False)
self.test_package_rbf_basic()
self.test_package_rbf_singleton()
self.test_package_rbf_additional_fees()
self.test_package_rbf_max_conflicts()
self.test_too_numerous_ancestors()
self.test_package_rbf_with_wrong_pkg_size()
self.test_insufficient_feerate()
self.test_wrong_conflict_cluster_size_linear()
self.test_wrong_conflict_cluster_size_parents_child()
self.test_wrong_conflict_cluster_size_parent_children()
self.test_0fee_package_rbf()
self.test_child_conflicts_parent_mempool_ancestor()
def test_package_rbf_basic(self):
self.log.info("Test that a child can pay to replace its parents' conflicts of cluster size 2")
node = self.nodes[0]
# Reuse the same coins so that the transactions conflict with one another.
parent_coin = self.coins.pop()
package_hex1, package_txns1 = self.create_simple_package(parent_coin, DEFAULT_FEE, DEFAULT_FEE)
package_hex2, package_txns2 = self.create_simple_package(parent_coin, DEFAULT_FEE, DEFAULT_CHILD_FEE)
node.submitpackage(package_hex1)
self.assert_mempool_contents(expected=package_txns1)
# Make sure 2nd node gets set up for basic package RBF
self.sync_all()
# Test run rejected because conflicts are not allowed in subpackage evaluation
testres = node.testmempoolaccept(package_hex2)
assert_equal(testres[0]["reject-reason"], "bip125-replacement-disallowed")
# But accepted during normal submission
submitres = node.submitpackage(package_hex2)
assert_equal(set(submitres["replaced-transactions"]), set([tx.rehash() for tx in package_txns1]))
self.assert_mempool_contents(expected=package_txns2)
# Make sure 2nd node gets a basic package RBF over p2p
self.sync_all()
self.generate(node, 1)
def test_package_rbf_singleton(self):
self.log.info("Test child can pay to replace a parent's single conflicted tx")
node = self.nodes[0]
# Make singleton tx to conflict with in next batch
singleton_coin = self.coins.pop()
singleton_tx = self.wallet.create_self_transfer(utxo_to_spend=singleton_coin)
node.sendrawtransaction(singleton_tx["hex"])
self.assert_mempool_contents(expected=[singleton_tx["tx"]])
package_hex, package_txns = self.create_simple_package(singleton_coin, DEFAULT_FEE, singleton_tx["fee"] * 2)
submitres = node.submitpackage(package_hex)
assert_equal(submitres["replaced-transactions"], [singleton_tx["tx"].rehash()])
self.assert_mempool_contents(expected=package_txns)
self.generate(node, 1)
def test_package_rbf_additional_fees(self):
self.log.info("Check Package RBF must increase the absolute fee")
node = self.nodes[0]
coin = self.coins.pop()
package_hex1, package_txns1 = self.create_simple_package(coin, parent_fee=DEFAULT_FEE, child_fee=DEFAULT_CHILD_FEE, heavy_child=True)
assert_greater_than_or_equal(1000, package_txns1[-1].get_vsize())
node.submitpackage(package_hex1)
self.assert_mempool_contents(expected=package_txns1)
PACKAGE_FEE = DEFAULT_FEE + DEFAULT_CHILD_FEE
PACKAGE_FEE_MINUS_ONE = PACKAGE_FEE - Decimal("0.00000001")
# Package 2 has a higher feerate but lower absolute fee
package_hex2, package_txns2 = self.create_simple_package(coin, parent_fee=DEFAULT_FEE, child_fee=DEFAULT_CHILD_FEE - Decimal("0.00000001"))
pkg_results2 = node.submitpackage(package_hex2)
assert_equal(f"package RBF failed: insufficient anti-DoS fees, rejecting replacement {package_txns2[1].rehash()}, less fees than conflicting txs; {PACKAGE_FEE_MINUS_ONE} < {PACKAGE_FEE}", pkg_results2["package_msg"])
self.assert_mempool_contents(expected=package_txns1)
self.log.info("Check replacement pays for incremental bandwidth")
package_hex3, package_txns3 = self.create_simple_package(coin, parent_fee=DEFAULT_FEE, child_fee=DEFAULT_CHILD_FEE)
pkg_results3 = node.submitpackage(package_hex3)
assert_equal(f"package RBF failed: insufficient anti-DoS fees, rejecting replacement {package_txns3[1].rehash()}, not enough additional fees to relay; 0.00 < 0.00000{sum([tx.get_vsize() for tx in package_txns3])}", pkg_results3["package_msg"])
self.assert_mempool_contents(expected=package_txns1)
self.generate(node, 1)
self.log.info("Check Package RBF must have strict cpfp structure")
coin = self.coins.pop()
package_hex4, package_txns4 = self.create_simple_package(coin, parent_fee=DEFAULT_FEE, child_fee=DEFAULT_CHILD_FEE)
node.submitpackage(package_hex4)
self.assert_mempool_contents(expected=package_txns4)
package_hex5, package_txns5 = self.create_simple_package(coin, parent_fee=DEFAULT_CHILD_FEE, child_fee=DEFAULT_CHILD_FEE - Decimal("0.00000001"))
pkg_results5 = node.submitpackage(package_hex5)
assert 'package RBF failed: package feerate is less than parent feerate' in pkg_results5["package_msg"]
self.assert_mempool_contents(expected=package_txns4)
self.generate(node, 1)
def test_package_rbf_max_conflicts(self):
node = self.nodes[0]
self.log.info("Check Package RBF cannot replace more than MAX_REPLACEMENT_CANDIDATES transactions")
num_coins = 51
parent_coins = self.coins[:num_coins]
del self.coins[:num_coins]
# Original transactions: 51 transactions with 1 descendants each -> 102 total transactions
size_two_clusters = []
for coin in parent_coins:
size_two_clusters.append(self.wallet.send_self_transfer_chain(from_node=node, chain_length=2, utxo_to_spend=coin))
expected_txns = [txn["tx"] for parent_child_txns in size_two_clusters for txn in parent_child_txns]
assert_equal(len(expected_txns), num_coins * 2)
self.assert_mempool_contents(expected=expected_txns)
# parent feeerate needs to be high enough for minrelay
# child feerate needs to be large enough to trigger package rbf with a very large parent and
# pay for all evicted fees. maxfeerate turned off for all submissions since child feerate
# is extremely high
parent_fee_per_conflict = 10000
child_feerate = 10000 * DEFAULT_FEE
# Conflict against all transactions by double-spending each parent, causing 102 evictions
package_parent = self.wallet.create_self_transfer_multi(utxos_to_spend=parent_coins, fee_per_output=parent_fee_per_conflict)
package_child = self.wallet.create_self_transfer(fee_rate=child_feerate, utxo_to_spend=package_parent["new_utxos"][0])
pkg_results = node.submitpackage([package_parent["hex"], package_child["hex"]], maxfeerate=0)
assert_equal(f"package RBF failed: too many potential replacements, rejecting replacement {package_child['tx'].rehash()}; too many potential replacements (102 > 100)\n", pkg_results["package_msg"])
self.assert_mempool_contents(expected=expected_txns)
# Make singleton tx to conflict with in next batch
singleton_coin = self.coins.pop()
singleton_tx = self.wallet.create_self_transfer(utxo_to_spend=singleton_coin)
node.sendrawtransaction(singleton_tx["hex"])
expected_txns.append(singleton_tx["tx"])
# Double-spend same set minus last, and double-spend singleton. This hits 101 evictions; should still fail.
# N.B. we can't RBF just a child tx in the clusters, as that would make resulting cluster of size 3.
double_spending_coins = parent_coins[:-1] + [singleton_coin]
package_parent = self.wallet.create_self_transfer_multi(utxos_to_spend=double_spending_coins, fee_per_output=parent_fee_per_conflict)
package_child = self.wallet.create_self_transfer(fee_rate=child_feerate, utxo_to_spend=package_parent["new_utxos"][0])
pkg_results = node.submitpackage([package_parent["hex"], package_child["hex"]], maxfeerate=0)
assert_equal(f"package RBF failed: too many potential replacements, rejecting replacement {package_child['tx'].rehash()}; too many potential replacements (101 > 100)\n", pkg_results["package_msg"])
self.assert_mempool_contents(expected=expected_txns)
# Finally, evict MAX_REPLACEMENT_CANDIDATES
package_parent = self.wallet.create_self_transfer_multi(utxos_to_spend=parent_coins[:-1], fee_per_output=parent_fee_per_conflict)
package_child = self.wallet.create_self_transfer(fee_rate=child_feerate, utxo_to_spend=package_parent["new_utxos"][0])
pkg_results = node.submitpackage([package_parent["hex"], package_child["hex"]], maxfeerate=0)
assert_equal(pkg_results["package_msg"], "success")
self.assert_mempool_contents(expected=[singleton_tx["tx"], size_two_clusters[-1][0]["tx"], size_two_clusters[-1][1]["tx"], package_parent["tx"], package_child["tx"]] )
self.generate(node, 1)
def test_too_numerous_ancestors(self):
self.log.info("Test that package RBF doesn't work with packages larger than 2 due to ancestors")
node = self.nodes[0]
coin = self.coins.pop()
package_hex1, package_txns1 = self.create_simple_package(coin, DEFAULT_FEE, DEFAULT_CHILD_FEE)
node.submitpackage(package_hex1)
self.assert_mempool_contents(expected=package_txns1)
# Double-spends the original package
self.ctr += 1
parent_result1 = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
coin2 = self.coins.pop()
# Added to make package too large for package RBF;
# it will enter mempool individually
self.ctr += 1
parent_result2 = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin2,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
# Child that spends both, violating cluster size rule due
# to in-mempool ancestry
self.ctr += 1
child_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_CHILD_FEE * COIN),
utxos_to_spend=[parent_result1["new_utxo"], parent_result2["new_utxo"]],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
package_hex2 = [parent_result1["hex"], parent_result2["hex"], child_result["hex"]]
package_txns2_succeed = [parent_result2["tx"]]
pkg_result = node.submitpackage(package_hex2)
assert_equal(pkg_result["package_msg"], 'package RBF failed: new transaction cannot have mempool ancestors')
self.assert_mempool_contents(expected=package_txns1 + package_txns2_succeed)
self.generate(node, 1)
def test_wrong_conflict_cluster_size_linear(self):
self.log.info("Test that conflicting with a cluster not sized two is rejected: linear chain")
node = self.nodes[0]
# Coins we will conflict with
coin1 = self.coins.pop()
coin2 = self.coins.pop()
coin3 = self.coins.pop()
# Three transactions chained; package RBF against any of these
# should be rejected
self.ctr += 1
parent_result = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin1,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
child_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[parent_result["new_utxo"], coin2],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
grandchild_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[child_result["new_utxos"][0], coin3],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
expected_txns = [parent_result["tx"], child_result["tx"], grandchild_result["tx"]]
for tx in expected_txns:
node.sendrawtransaction(tx.serialize().hex())
self.assert_mempool_contents(expected=expected_txns)
# Now make conflicting packages for each coin
package_hex1, package_txns1 = self.create_simple_package(coin1, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex1)
assert_equal(f"package RBF failed: {parent_result['tx'].rehash()} has 2 descendants, max 1 allowed", package_result["package_msg"])
package_hex2, package_txns2 = self.create_simple_package(coin2, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex2)
assert_equal(f"package RBF failed: {child_result['tx'].rehash()} has both ancestor and descendant, exceeding cluster limit of 2", package_result["package_msg"])
package_hex3, package_txns3 = self.create_simple_package(coin3, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex3)
assert_equal(f"package RBF failed: {grandchild_result['tx'].rehash()} has 2 ancestors, max 1 allowed", package_result["package_msg"])
# Check that replacements were actually rejected
self.assert_mempool_contents(expected=expected_txns)
self.generate(node, 1)
def test_wrong_conflict_cluster_size_parents_child(self):
self.log.info("Test that conflicting with a cluster not sized two is rejected: two parents one child")
node = self.nodes[0]
# Coins we will conflict with
coin1 = self.coins.pop()
coin2 = self.coins.pop()
coin3 = self.coins.pop()
self.ctr += 1
parent1_result = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin1,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
parent2_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[coin2],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
child_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[parent1_result["new_utxo"], parent2_result["new_utxos"][0], coin3],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
expected_txns = [parent1_result["tx"], parent2_result["tx"], child_result["tx"]]
for tx in expected_txns:
node.sendrawtransaction(tx.serialize().hex())
self.assert_mempool_contents(expected=expected_txns)
# Now make conflicting packages for each coin
package_hex1, package_txns1 = self.create_simple_package(coin1, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex1)
assert_equal(f"package RBF failed: {parent1_result['tx'].rehash()} is not the only parent of child {child_result['tx'].rehash()}", package_result["package_msg"])
package_hex2, package_txns2 = self.create_simple_package(coin2, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex2)
assert_equal(f"package RBF failed: {parent2_result['tx'].rehash()} is not the only parent of child {child_result['tx'].rehash()}", package_result["package_msg"])
package_hex3, package_txns3 = self.create_simple_package(coin3, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex3)
assert_equal(f"package RBF failed: {child_result['tx'].rehash()} has 2 ancestors, max 1 allowed", package_result["package_msg"])
# Check that replacements were actually rejected
self.assert_mempool_contents(expected=expected_txns)
self.generate(node, 1)
def test_wrong_conflict_cluster_size_parent_children(self):
self.log.info("Test that conflicting with a cluster not sized two is rejected: one parent two children")
node = self.nodes[0]
# Coins we will conflict with
coin1 = self.coins.pop()
coin2 = self.coins.pop()
coin3 = self.coins.pop()
self.ctr += 1
parent_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
num_outputs=2,
utxos_to_spend=[coin1],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
child1_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[parent_result["new_utxos"][0], coin2],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
self.ctr += 1
child2_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_FEE * COIN),
utxos_to_spend=[parent_result["new_utxos"][1], coin3],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
# Submit them to mempool
expected_txns = [parent_result["tx"], child1_result["tx"], child2_result["tx"]]
for tx in expected_txns:
node.sendrawtransaction(tx.serialize().hex())
self.assert_mempool_contents(expected=expected_txns)
# Now make conflicting packages for each coin
package_hex1, package_txns1 = self.create_simple_package(coin1, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex1)
assert_equal(f"package RBF failed: {parent_result['tx'].rehash()} has 2 descendants, max 1 allowed", package_result["package_msg"])
package_hex2, package_txns2 = self.create_simple_package(coin2, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex2)
assert_equal(f"package RBF failed: {child1_result['tx'].rehash()} is not the only child of parent {parent_result['tx'].rehash()}", package_result["package_msg"])
package_hex3, package_txns3 = self.create_simple_package(coin3, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_result = node.submitpackage(package_hex3)
assert_equal(f"package RBF failed: {child2_result['tx'].rehash()} is not the only child of parent {parent_result['tx'].rehash()}", package_result["package_msg"])
# Check that replacements were actually rejected
self.assert_mempool_contents(expected=expected_txns)
self.generate(node, 1)
def test_package_rbf_with_wrong_pkg_size(self):
self.log.info("Test that package RBF doesn't work with packages larger than 2 due to pkg size")
node = self.nodes[0]
coin1 = self.coins.pop()
coin2 = self.coins.pop()
# Two packages to require multiple direct conflicts, easier to set up illicit pkg size
package_hex1, package_txns1 = self.create_simple_package(coin1, DEFAULT_FEE, DEFAULT_CHILD_FEE)
package_hex2, package_txns2 = self.create_simple_package(coin2, DEFAULT_FEE, DEFAULT_CHILD_FEE)
node.submitpackage(package_hex1)
node.submitpackage(package_hex2)
self.assert_mempool_contents(expected=package_txns1 + package_txns2)
assert_equal(len(node.getrawmempool()), 4)
# Double-spends the first package
self.ctr += 1
parent_result1 = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin1,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
# Double-spends the second package
self.ctr += 1
parent_result2 = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin2,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
# Child that spends both, violating cluster size rule due
# to pkg size
self.ctr += 1
child_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_CHILD_FEE * COIN),
utxos_to_spend=[parent_result1["new_utxo"], parent_result2["new_utxo"]],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
package_hex3 = [parent_result1["hex"], parent_result2["hex"], child_result["hex"]]
pkg_result = node.submitpackage(package_hex3)
assert_equal(pkg_result["package_msg"], 'package RBF failed: package must be 1-parent-1-child')
self.assert_mempool_contents(expected=package_txns1 + package_txns2)
self.generate(node, 1)
def test_insufficient_feerate(self):
self.log.info("Check Package RBF must beat feerate of direct conflict")
node = self.nodes[0]
coin = self.coins.pop()
# Non-cpfp structure
package_hex1, package_txns1 = self.create_simple_package(coin, parent_fee=DEFAULT_CHILD_FEE, child_fee=DEFAULT_FEE)
node.submitpackage(package_hex1)
self.assert_mempool_contents(expected=package_txns1)
# Package 2 feerate is below the feerate of directly conflicted parent, so it fails even though
# total fees are higher than the original package
package_hex2, package_txns2 = self.create_simple_package(coin, parent_fee=DEFAULT_CHILD_FEE - Decimal("0.00000001"), child_fee=DEFAULT_CHILD_FEE)
pkg_results2 = node.submitpackage(package_hex2)
assert_equal(pkg_results2["package_msg"], 'package RBF failed: insufficient feerate: does not improve feerate diagram')
self.assert_mempool_contents(expected=package_txns1)
self.generate(node, 1)
def test_0fee_package_rbf(self):
self.log.info("Test package RBF: TRUC 0-fee parent + high-fee child replaces parent's conflicts")
node = self.nodes[0]
# Reuse the same coins so that the transactions conflict with one another.
self.wallet.rescan_utxos()
parent_coin = self.wallet.get_utxo(confirmed_only=True)
# package1 pays default fee on both transactions
parent1 = self.wallet.create_self_transfer(utxo_to_spend=parent_coin, version=3)
child1 = self.wallet.create_self_transfer(utxo_to_spend=parent1["new_utxo"], version=3)
package_hex1 = [parent1["hex"], child1["hex"]]
fees_package1 = parent1["fee"] + child1["fee"]
submitres1 = node.submitpackage(package_hex1)
assert_equal(submitres1["package_msg"], "success")
self.assert_mempool_contents([parent1["tx"], child1["tx"]])
# package2 has a 0-fee parent (conflicting with package1) and very high fee child
parent2 = self.wallet.create_self_transfer(utxo_to_spend=parent_coin, fee=0, fee_rate=0, version=3)
child2 = self.wallet.create_self_transfer(utxo_to_spend=parent2["new_utxo"], fee=fees_package1*10, version=3)
package_hex2 = [parent2["hex"], child2["hex"]]
submitres2 = node.submitpackage(package_hex2)
assert_equal(submitres2["package_msg"], "success")
assert_equal(set(submitres2["replaced-transactions"]), set([parent1["txid"], child1["txid"]]))
self.assert_mempool_contents([parent2["tx"], child2["tx"]])
self.generate(node, 1)
def test_child_conflicts_parent_mempool_ancestor(self):
fill_mempool(self, self.nodes[0])
# Reset coins since we filled the mempool with current coins
self.coins = self.wallet.get_utxos(mark_as_spent=False, confirmed_only=True)
self.log.info("Test that package RBF doesn't have issues with mempool<->package conflicts via inconsistency")
node = self.nodes[0]
coin = self.coins.pop()
self.ctr += 1
grandparent_result = self.wallet.create_self_transfer(
fee=DEFAULT_FEE,
utxo_to_spend=coin,
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
node.sendrawtransaction(grandparent_result["hex"])
# Now make package of two descendants that looks
# like a cpfp where the parent can't get in on its own
self.ctr += 1
parent_result = self.wallet.create_self_transfer(
fee_rate=Decimal('0.00001000'),
utxo_to_spend=grandparent_result["new_utxo"],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
# Last tx double-spends grandparent's coin,
# which is not inside the current package
self.ctr += 1
child_result = self.wallet.create_self_transfer_multi(
fee_per_output=int(DEFAULT_CHILD_FEE * COIN),
utxos_to_spend=[parent_result["new_utxo"], coin],
sequence=MAX_BIP125_RBF_SEQUENCE - self.ctr,
)
pkg_result = node.submitpackage([parent_result["hex"], child_result["hex"]])
assert_equal(pkg_result["package_msg"], 'package RBF failed: new transaction cannot have mempool ancestors')
mempool_info = node.getrawmempool()
assert grandparent_result["txid"] in mempool_info
assert parent_result["txid"] not in mempool_info
assert child_result["txid"] not in mempool_info
if __name__ == "__main__":
PackageRBFTest().main()
|