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Diffstat (limited to 'test/functional/wallet_abandonconflict.py')
| -rwxr-xr-x | test/functional/wallet_abandonconflict.py | 164 |
1 files changed, 164 insertions, 0 deletions
diff --git a/test/functional/wallet_abandonconflict.py b/test/functional/wallet_abandonconflict.py new file mode 100755 index 0000000000..8fb860cd7e --- /dev/null +++ b/test/functional/wallet_abandonconflict.py @@ -0,0 +1,164 @@ +#!/usr/bin/env python3 +# Copyright (c) 2014-2017 The Bitcoin Core developers +# Distributed under the MIT software license, see the accompanying +# file COPYING or http://www.opensource.org/licenses/mit-license.php. +"""Test the abandontransaction RPC. + + The abandontransaction RPC marks a transaction and all its in-wallet + descendants as abandoned which allows their inputs to be respent. It can be + used to replace "stuck" or evicted transactions. It only works on transactions + which are not included in a block and are not currently in the mempool. It has + no effect on transactions which are already abandoned. +""" +from test_framework.test_framework import BitcoinTestFramework +from test_framework.util import * + + +class AbandonConflictTest(BitcoinTestFramework): + def set_test_params(self): + self.num_nodes = 2 + self.extra_args = [["-minrelaytxfee=0.00001"], []] + + def run_test(self): + self.nodes[1].generate(100) + sync_blocks(self.nodes) + balance = self.nodes[0].getbalance() + txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) + txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) + txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) + sync_mempools(self.nodes) + self.nodes[1].generate(1) + + # Can not abandon non-wallet transaction + assert_raises_rpc_error(-5, 'Invalid or non-wallet transaction id', lambda: self.nodes[0].abandontransaction(txid='ff' * 32)) + # Can not abandon confirmed transaction + assert_raises_rpc_error(-5, 'Transaction not eligible for abandonment', lambda: self.nodes[0].abandontransaction(txid=txA)) + + sync_blocks(self.nodes) + newbalance = self.nodes[0].getbalance() + assert(balance - newbalance < Decimal("0.001")) #no more than fees lost + balance = newbalance + + # Disconnect nodes so node0's transactions don't get into node1's mempool + disconnect_nodes(self.nodes[0], 1) + + # Identify the 10btc outputs + nA = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txA, 1)["vout"]) if vout["value"] == Decimal("10")) + nB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txB, 1)["vout"]) if vout["value"] == Decimal("10")) + nC = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txC, 1)["vout"]) if vout["value"] == Decimal("10")) + + inputs =[] + # spend 10btc outputs from txA and txB + inputs.append({"txid":txA, "vout":nA}) + inputs.append({"txid":txB, "vout":nB}) + outputs = {} + + outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998") + outputs[self.nodes[1].getnewaddress()] = Decimal("5") + signed = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs)) + txAB1 = self.nodes[0].sendrawtransaction(signed["hex"]) + + # Identify the 14.99998btc output + nAB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txAB1, 1)["vout"]) if vout["value"] == Decimal("14.99998")) + + #Create a child tx spending AB1 and C + inputs = [] + inputs.append({"txid":txAB1, "vout":nAB}) + inputs.append({"txid":txC, "vout":nC}) + outputs = {} + outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996") + signed2 = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs)) + txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"]) + + # In mempool txs from self should increase balance from change + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance - Decimal("30") + Decimal("24.9996")) + balance = newbalance + + # Restart the node with a higher min relay fee so the parent tx is no longer in mempool + # TODO: redo with eviction + self.stop_node(0) + self.start_node(0, extra_args=["-minrelaytxfee=0.0001"]) + + # Verify txs no longer in either node's mempool + assert_equal(len(self.nodes[0].getrawmempool()), 0) + assert_equal(len(self.nodes[1].getrawmempool()), 0) + + # Not in mempool txs from self should only reduce balance + # inputs are still spent, but change not received + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance - Decimal("24.9996")) + # Unconfirmed received funds that are not in mempool, also shouldn't show + # up in unconfirmed balance + unconfbalance = self.nodes[0].getunconfirmedbalance() + self.nodes[0].getbalance() + assert_equal(unconfbalance, newbalance) + # Also shouldn't show up in listunspent + assert(not txABC2 in [utxo["txid"] for utxo in self.nodes[0].listunspent(0)]) + balance = newbalance + + # Abandon original transaction and verify inputs are available again + # including that the child tx was also abandoned + self.nodes[0].abandontransaction(txAB1) + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance + Decimal("30")) + balance = newbalance + + # Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned + self.stop_node(0) + self.start_node(0, extra_args=["-minrelaytxfee=0.00001"]) + assert_equal(len(self.nodes[0].getrawmempool()), 0) + assert_equal(self.nodes[0].getbalance(), balance) + + # But if its received again then it is unabandoned + # And since now in mempool, the change is available + # But its child tx remains abandoned + self.nodes[0].sendrawtransaction(signed["hex"]) + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance - Decimal("20") + Decimal("14.99998")) + balance = newbalance + + # Send child tx again so its unabandoned + self.nodes[0].sendrawtransaction(signed2["hex"]) + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996")) + balance = newbalance + + # Remove using high relay fee again + self.stop_node(0) + self.start_node(0, extra_args=["-minrelaytxfee=0.0001"]) + assert_equal(len(self.nodes[0].getrawmempool()), 0) + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance - Decimal("24.9996")) + balance = newbalance + + # Create a double spend of AB1 by spending again from only A's 10 output + # Mine double spend from node 1 + inputs =[] + inputs.append({"txid":txA, "vout":nA}) + outputs = {} + outputs[self.nodes[1].getnewaddress()] = Decimal("9.9999") + tx = self.nodes[0].createrawtransaction(inputs, outputs) + signed = self.nodes[0].signrawtransaction(tx) + self.nodes[1].sendrawtransaction(signed["hex"]) + self.nodes[1].generate(1) + + connect_nodes(self.nodes[0], 1) + sync_blocks(self.nodes) + + # Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted + newbalance = self.nodes[0].getbalance() + assert_equal(newbalance, balance + Decimal("20")) + balance = newbalance + + # There is currently a minor bug around this and so this test doesn't work. See Issue #7315 + # Invalidate the block with the double spend and B's 10 BTC output should no longer be available + # Don't think C's should either + self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash()) + newbalance = self.nodes[0].getbalance() + #assert_equal(newbalance, balance - Decimal("10")) + self.log.info("If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer") + self.log.info("conflicted has not resumed causing its inputs to be seen as spent. See Issue #7315") + self.log.info(str(balance) + " -> " + str(newbalance) + " ?") + +if __name__ == '__main__': + AbandonConflictTest().main() |