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-rwxr-xr-xtest/functional/wallet_abandonconflict.py164
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diff --git a/test/functional/wallet_abandonconflict.py b/test/functional/wallet_abandonconflict.py
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+#!/usr/bin/env python3
+# Copyright (c) 2014-2017 The Bitcoin Core developers
+# Distributed under the MIT software license, see the accompanying
+# file COPYING or http://www.opensource.org/licenses/mit-license.php.
+"""Test the abandontransaction RPC.
+
+ The abandontransaction RPC marks a transaction and all its in-wallet
+ descendants as abandoned which allows their inputs to be respent. It can be
+ used to replace "stuck" or evicted transactions. It only works on transactions
+ which are not included in a block and are not currently in the mempool. It has
+ no effect on transactions which are already abandoned.
+"""
+from test_framework.test_framework import BitcoinTestFramework
+from test_framework.util import *
+
+
+class AbandonConflictTest(BitcoinTestFramework):
+ def set_test_params(self):
+ self.num_nodes = 2
+ self.extra_args = [["-minrelaytxfee=0.00001"], []]
+
+ def run_test(self):
+ self.nodes[1].generate(100)
+ sync_blocks(self.nodes)
+ balance = self.nodes[0].getbalance()
+ txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+ txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+ txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+ sync_mempools(self.nodes)
+ self.nodes[1].generate(1)
+
+ # Can not abandon non-wallet transaction
+ assert_raises_rpc_error(-5, 'Invalid or non-wallet transaction id', lambda: self.nodes[0].abandontransaction(txid='ff' * 32))
+ # Can not abandon confirmed transaction
+ assert_raises_rpc_error(-5, 'Transaction not eligible for abandonment', lambda: self.nodes[0].abandontransaction(txid=txA))
+
+ sync_blocks(self.nodes)
+ newbalance = self.nodes[0].getbalance()
+ assert(balance - newbalance < Decimal("0.001")) #no more than fees lost
+ balance = newbalance
+
+ # Disconnect nodes so node0's transactions don't get into node1's mempool
+ disconnect_nodes(self.nodes[0], 1)
+
+ # Identify the 10btc outputs
+ nA = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txA, 1)["vout"]) if vout["value"] == Decimal("10"))
+ nB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txB, 1)["vout"]) if vout["value"] == Decimal("10"))
+ nC = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txC, 1)["vout"]) if vout["value"] == Decimal("10"))
+
+ inputs =[]
+ # spend 10btc outputs from txA and txB
+ inputs.append({"txid":txA, "vout":nA})
+ inputs.append({"txid":txB, "vout":nB})
+ outputs = {}
+
+ outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998")
+ outputs[self.nodes[1].getnewaddress()] = Decimal("5")
+ signed = self.nodes[0].signrawtransactionwithwallet(self.nodes[0].createrawtransaction(inputs, outputs))
+ txAB1 = self.nodes[0].sendrawtransaction(signed["hex"])
+
+ # Identify the 14.99998btc output
+ nAB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txAB1, 1)["vout"]) if vout["value"] == Decimal("14.99998"))
+
+ #Create a child tx spending AB1 and C
+ inputs = []
+ inputs.append({"txid":txAB1, "vout":nAB})
+ inputs.append({"txid":txC, "vout":nC})
+ outputs = {}
+ outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996")
+ signed2 = self.nodes[0].signrawtransactionwithwallet(self.nodes[0].createrawtransaction(inputs, outputs))
+ txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"])
+
+ # In mempool txs from self should increase balance from change
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance - Decimal("30") + Decimal("24.9996"))
+ balance = newbalance
+
+ # Restart the node with a higher min relay fee so the parent tx is no longer in mempool
+ # TODO: redo with eviction
+ self.stop_node(0)
+ self.start_node(0, extra_args=["-minrelaytxfee=0.0001"])
+
+ # Verify txs no longer in either node's mempool
+ assert_equal(len(self.nodes[0].getrawmempool()), 0)
+ assert_equal(len(self.nodes[1].getrawmempool()), 0)
+
+ # Not in mempool txs from self should only reduce balance
+ # inputs are still spent, but change not received
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance - Decimal("24.9996"))
+ # Unconfirmed received funds that are not in mempool, also shouldn't show
+ # up in unconfirmed balance
+ unconfbalance = self.nodes[0].getunconfirmedbalance() + self.nodes[0].getbalance()
+ assert_equal(unconfbalance, newbalance)
+ # Also shouldn't show up in listunspent
+ assert(not txABC2 in [utxo["txid"] for utxo in self.nodes[0].listunspent(0)])
+ balance = newbalance
+
+ # Abandon original transaction and verify inputs are available again
+ # including that the child tx was also abandoned
+ self.nodes[0].abandontransaction(txAB1)
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance + Decimal("30"))
+ balance = newbalance
+
+ # Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned
+ self.stop_node(0)
+ self.start_node(0, extra_args=["-minrelaytxfee=0.00001"])
+ assert_equal(len(self.nodes[0].getrawmempool()), 0)
+ assert_equal(self.nodes[0].getbalance(), balance)
+
+ # But if it is received again then it is unabandoned
+ # And since now in mempool, the change is available
+ # But its child tx remains abandoned
+ self.nodes[0].sendrawtransaction(signed["hex"])
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance - Decimal("20") + Decimal("14.99998"))
+ balance = newbalance
+
+ # Send child tx again so it is unabandoned
+ self.nodes[0].sendrawtransaction(signed2["hex"])
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996"))
+ balance = newbalance
+
+ # Remove using high relay fee again
+ self.stop_node(0)
+ self.start_node(0, extra_args=["-minrelaytxfee=0.0001"])
+ assert_equal(len(self.nodes[0].getrawmempool()), 0)
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance - Decimal("24.9996"))
+ balance = newbalance
+
+ # Create a double spend of AB1 by spending again from only A's 10 output
+ # Mine double spend from node 1
+ inputs =[]
+ inputs.append({"txid":txA, "vout":nA})
+ outputs = {}
+ outputs[self.nodes[1].getnewaddress()] = Decimal("9.9999")
+ tx = self.nodes[0].createrawtransaction(inputs, outputs)
+ signed = self.nodes[0].signrawtransactionwithwallet(tx)
+ self.nodes[1].sendrawtransaction(signed["hex"])
+ self.nodes[1].generate(1)
+
+ connect_nodes(self.nodes[0], 1)
+ sync_blocks(self.nodes)
+
+ # Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted
+ newbalance = self.nodes[0].getbalance()
+ assert_equal(newbalance, balance + Decimal("20"))
+ balance = newbalance
+
+ # There is currently a minor bug around this and so this test doesn't work. See Issue #7315
+ # Invalidate the block with the double spend and B's 10 BTC output should no longer be available
+ # Don't think C's should either
+ self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
+ newbalance = self.nodes[0].getbalance()
+ #assert_equal(newbalance, balance - Decimal("10"))
+ self.log.info("If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer")
+ self.log.info("conflicted has not resumed causing its inputs to be seen as spent. See Issue #7315")
+ self.log.info(str(balance) + " -> " + str(newbalance) + " ?")
+
+if __name__ == '__main__':
+ AbandonConflictTest().main()