diff options
Diffstat (limited to 'test/functional/feature_rbf.py')
| -rwxr-xr-x | test/functional/feature_rbf.py | 108 |
1 files changed, 48 insertions, 60 deletions
diff --git a/test/functional/feature_rbf.py b/test/functional/feature_rbf.py index ff7c2b23bf..1496c5d958 100755 --- a/test/functional/feature_rbf.py +++ b/test/functional/feature_rbf.py @@ -1,5 +1,5 @@ #!/usr/bin/env python3 -# Copyright (c) 2014-2018 The Bitcoin Core developers +# Copyright (c) 2014-2019 The Bitcoin Core developers # Distributed under the MIT software license, see the accompanying # file COPYING or http://www.opensource.org/licenses/mit-license.php. """Test the RBF code.""" @@ -9,12 +9,12 @@ from decimal import Decimal from test_framework.messages import COIN, COutPoint, CTransaction, CTxIn, CTxOut from test_framework.script import CScript, OP_DROP from test_framework.test_framework import BitcoinTestFramework -from test_framework.util import assert_equal, assert_raises_rpc_error, bytes_to_hex_str, satoshi_round +from test_framework.util import assert_equal, assert_raises_rpc_error, satoshi_round MAX_REPLACEMENT_LIMIT = 100 def txToHex(tx): - return bytes_to_hex_str(tx.serialize()) + return tx.serialize().hex() def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])): """Create a txout with a given amount and scriptPubKey @@ -46,7 +46,7 @@ def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])): signed_tx = node.signrawtransactionwithwallet(txToHex(tx2)) - txid = node.sendrawtransaction(signed_tx['hex'], True) + txid = node.sendrawtransaction(signed_tx['hex'], 0) # If requested, ensure txouts are confirmed. if confirmed: @@ -56,7 +56,7 @@ def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])): new_size = len(node.getrawmempool()) # Error out if we have something stuck in the mempool, as this # would likely be a bug. - assert(new_size < mempool_size) + assert new_size < mempool_size mempool_size = new_size return COutPoint(int(txid, 16), 0) @@ -64,7 +64,7 @@ def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])): class ReplaceByFeeTest(BitcoinTestFramework): def set_test_params(self): - self.num_nodes = 2 + self.num_nodes = 1 self.extra_args = [ [ "-maxorphantx=1000", @@ -74,9 +74,6 @@ class ReplaceByFeeTest(BitcoinTestFramework): "-limitdescendantcount=200", "-limitdescendantsize=101", ], - [ - "-mempoolreplacement=0", - ], ] def skip_test_if_missing_module(self): @@ -136,7 +133,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) - tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) + tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0) self.sync_all() @@ -147,32 +144,23 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1b_hex = txToHex(tx1b) # This will raise an exception due to insufficient fee - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True) - # This will raise an exception due to transaction replacement being disabled - assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0) # Extra 0.1 BTC fee tx1b = CTransaction() tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)] tx1b.vout = [CTxOut(int(0.9 * COIN), CScript([b'b' * 35]))] tx1b_hex = txToHex(tx1b) - # Replacement still disabled even with "enough fee" - assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True) # Works when enabled - tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True) + tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0) mempool = self.nodes[0].getrawmempool() - assert (tx1a_txid not in mempool) - assert (tx1b_txid in mempool) + assert tx1a_txid not in mempool + assert tx1b_txid in mempool assert_equal(tx1b_hex, self.nodes[0].getrawtransaction(tx1b_txid)) - # Second node is running mempoolreplacement=0, will not replace originally-seen txn - mempool = self.nodes[1].getrawmempool() - assert tx1a_txid in mempool - assert tx1b_txid not in mempool - def test_doublespend_chain(self): """Doublespend of a long chain""" @@ -188,7 +176,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx.vin = [CTxIn(prevout, nSequence=0)] tx.vout = [CTxOut(remaining_value, CScript([1, OP_DROP] * 15 + [1]))] tx_hex = txToHex(tx) - txid = self.nodes[0].sendrawtransaction(tx_hex, True) + txid = self.nodes[0].sendrawtransaction(tx_hex, 0) chain_txids.append(txid) prevout = COutPoint(int(txid, 16), 0) @@ -200,18 +188,18 @@ class ReplaceByFeeTest(BitcoinTestFramework): dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception due to insufficient fee - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0) # Accepted with sufficient fee dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] dbl_tx.vout = [CTxOut(1 * COIN, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) - self.nodes[0].sendrawtransaction(dbl_tx_hex, True) + self.nodes[0].sendrawtransaction(dbl_tx_hex, 0) mempool = self.nodes[0].getrawmempool() for doublespent_txid in chain_txids: - assert(doublespent_txid not in mempool) + assert doublespent_txid not in mempool def test_doublespend_tree(self): """Doublespend of a big tree of transactions""" @@ -236,8 +224,8 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx.vout = vout tx_hex = txToHex(tx) - assert(len(tx.serialize()) < 100000) - txid = self.nodes[0].sendrawtransaction(tx_hex, True) + assert len(tx.serialize()) < 100000 + txid = self.nodes[0].sendrawtransaction(tx_hex, 0) yield tx _total_txs[0] += 1 @@ -261,20 +249,20 @@ class ReplaceByFeeTest(BitcoinTestFramework): dbl_tx.vout = [CTxOut(initial_nValue - fee * n, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception due to insufficient fee - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0) # 1 BTC fee is enough dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] dbl_tx.vout = [CTxOut(initial_nValue - fee * n - 1 * COIN, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) - self.nodes[0].sendrawtransaction(dbl_tx_hex, True) + self.nodes[0].sendrawtransaction(dbl_tx_hex, 0) mempool = self.nodes[0].getrawmempool() for tx in tree_txs: tx.rehash() - assert (tx.hash not in mempool) + assert tx.hash not in mempool # Try again, but with more total transactions than the "max txs # double-spent at once" anti-DoS limit. @@ -289,7 +277,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): dbl_tx.vout = [CTxOut(initial_nValue - 2 * fee * n, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception - assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, True) + assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0) for tx in tree_txs: tx.rehash() @@ -303,7 +291,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) - self.nodes[0].sendrawtransaction(tx1a_hex, True) + self.nodes[0].sendrawtransaction(tx1a_hex, 0) # Higher fee, but the fee per KB is much lower, so the replacement is # rejected. @@ -313,7 +301,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1b_hex = txToHex(tx1b) # This will raise an exception due to insufficient fee - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0) def test_spends_of_conflicting_outputs(self): """Replacements that spend conflicting tx outputs are rejected""" @@ -324,7 +312,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a.vin = [CTxIn(utxo1, nSequence=0)] tx1a.vout = [CTxOut(int(1.1 * COIN), CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) - tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) + tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0) tx1a_txid = int(tx1a_txid, 16) @@ -336,14 +324,14 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2_hex = txToHex(tx2) # This will raise an exception - assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True) + assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0) # Spend tx1a's output to test the indirect case. tx1b = CTransaction() tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)] tx1b.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1b_hex = txToHex(tx1b) - tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True) + tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0) tx1b_txid = int(tx1b_txid, 16) tx2 = CTransaction() @@ -353,7 +341,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2_hex = txToHex(tx2) # This will raise an exception - assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True) + assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0) def test_new_unconfirmed_inputs(self): """Replacements that add new unconfirmed inputs are rejected""" @@ -364,7 +352,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1.vin = [CTxIn(confirmed_utxo)] tx1.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1_hex = txToHex(tx1) - self.nodes[0].sendrawtransaction(tx1_hex, True) + self.nodes[0].sendrawtransaction(tx1_hex, 0) tx2 = CTransaction() tx2.vin = [CTxIn(confirmed_utxo), CTxIn(unconfirmed_utxo)] @@ -372,7 +360,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2_hex = txToHex(tx2) # This will raise an exception - assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, True) + assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, 0) def test_too_many_replacements(self): """Replacements that evict too many transactions are rejected""" @@ -394,7 +382,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): splitting_tx.vout = outputs splitting_tx_hex = txToHex(splitting_tx) - txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, True) + txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, 0) txid = int(txid, 16) # Now spend each of those outputs individually @@ -403,7 +391,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)] tx_i.vout = [CTxOut(split_value - fee, CScript([b'a' * 35]))] tx_i_hex = txToHex(tx_i) - self.nodes[0].sendrawtransaction(tx_i_hex, True) + self.nodes[0].sendrawtransaction(tx_i_hex, 0) # Now create doublespend of the whole lot; should fail. # Need a big enough fee to cover all spending transactions and have @@ -418,14 +406,14 @@ class ReplaceByFeeTest(BitcoinTestFramework): double_tx_hex = txToHex(double_tx) # This will raise an exception - assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, True) + assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, 0) # If we remove an input, it should pass double_tx = CTransaction() double_tx.vin = inputs[0:-1] double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))] double_tx_hex = txToHex(double_tx) - self.nodes[0].sendrawtransaction(double_tx_hex, True) + self.nodes[0].sendrawtransaction(double_tx_hex, 0) def test_opt_in(self): """Replacing should only work if orig tx opted in""" @@ -436,7 +424,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)] tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) - tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) + tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0) # This transaction isn't shown as replaceable assert_equal(self.nodes[0].getmempoolentry(tx1a_txid)['bip125-replaceable'], False) @@ -448,7 +436,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1b_hex = txToHex(tx1b) # This will raise an exception - assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, True) + assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, 0) tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN)) @@ -457,7 +445,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)] tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx2a_hex = txToHex(tx2a) - tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True) + tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, 0) # Still shouldn't be able to double-spend tx2b = CTransaction() @@ -466,7 +454,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2b_hex = txToHex(tx2b) # This will raise an exception - assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, True) + assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, 0) # Now create a new transaction that spends from tx1a and tx2a # opt-in on one of the inputs @@ -481,7 +469,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx3a.vout = [CTxOut(int(0.9*COIN), CScript([b'c'])), CTxOut(int(0.9*COIN), CScript([b'd']))] tx3a_hex = txToHex(tx3a) - tx3a_txid = self.nodes[0].sendrawtransaction(tx3a_hex, True) + tx3a_txid = self.nodes[0].sendrawtransaction(tx3a_hex, 0) # This transaction is shown as replaceable assert_equal(self.nodes[0].getmempoolentry(tx3a_txid)['bip125-replaceable'], True) @@ -496,10 +484,10 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx3c.vout = [CTxOut(int(0.5 * COIN), CScript([b'f' * 35]))] tx3c_hex = txToHex(tx3c) - self.nodes[0].sendrawtransaction(tx3b_hex, True) + self.nodes[0].sendrawtransaction(tx3b_hex, 0) # If tx3b was accepted, tx3c won't look like a replacement, # but make sure it is accepted anyway - self.nodes[0].sendrawtransaction(tx3c_hex, True) + self.nodes[0].sendrawtransaction(tx3c_hex, 0) def test_prioritised_transactions(self): # Ensure that fee deltas used via prioritisetransaction are @@ -512,7 +500,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) - tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) + tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0) # Higher fee, but the actual fee per KB is much lower. tx1b = CTransaction() @@ -521,15 +509,15 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1b_hex = txToHex(tx1b) # Verify tx1b cannot replace tx1a. - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0) # Use prioritisetransaction to set tx1a's fee to 0. self.nodes[0].prioritisetransaction(txid=tx1a_txid, fee_delta=int(-0.1*COIN)) # Now tx1b should be able to replace tx1a - tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True) + tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0) - assert(tx1b_txid in self.nodes[0].getrawmempool()) + assert tx1b_txid in self.nodes[0].getrawmempool() # 2. Check that absolute fee checks use modified fee. tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN)) @@ -538,7 +526,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0)] tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx2a_hex = txToHex(tx2a) - self.nodes[0].sendrawtransaction(tx2a_hex, True) + self.nodes[0].sendrawtransaction(tx2a_hex, 0) # Lower fee, but we'll prioritise it tx2b = CTransaction() @@ -548,15 +536,15 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2b_hex = txToHex(tx2b) # Verify tx2b cannot replace tx2a. - assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b_hex, True) + assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b_hex, 0) # Now prioritise tx2b to have a higher modified fee self.nodes[0].prioritisetransaction(txid=tx2b.hash, fee_delta=int(0.1*COIN)) # tx2b should now be accepted - tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, True) + tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, 0) - assert(tx2b_txid in self.nodes[0].getrawmempool()) + assert tx2b_txid in self.nodes[0].getrawmempool() def test_rpc(self): us0 = self.nodes[0].listunspent()[0] |