diff options
Diffstat (limited to 'test/functional/feature_rbf.py')
| -rwxr-xr-x | test/functional/feature_rbf.py | 46 |
1 files changed, 23 insertions, 23 deletions
diff --git a/test/functional/feature_rbf.py b/test/functional/feature_rbf.py index d6ab5ecc37..c087960782 100755 --- a/test/functional/feature_rbf.py +++ b/test/functional/feature_rbf.py @@ -123,7 +123,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a = CTransaction() tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) @@ -132,7 +132,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Should fail because we haven't changed the fee tx1b = CTransaction() tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1b.vout = [CTxOut(1*COIN, CScript([b'b']))] + tx1b.vout = [CTxOut(1 * COIN, CScript([b'b' * 35]))] tx1b_hex = txToHex(tx1b) # This will raise an exception due to insufficient fee @@ -143,7 +143,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Extra 0.1 BTC fee tx1b = CTransaction() tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))] + tx1b.vout = [CTxOut(int(0.9 * COIN), CScript([b'b' * 35]))] tx1b_hex = txToHex(tx1b) # Replacement still disabled even with "enough fee" assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True) @@ -175,7 +175,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): remaining_value -= 1*COIN tx = CTransaction() tx.vin = [CTxIn(prevout, nSequence=0)] - tx.vout = [CTxOut(remaining_value, CScript([1]))] + tx.vout = [CTxOut(remaining_value, CScript([1, OP_DROP] * 15 + [1]))] tx_hex = txToHex(tx) txid = self.nodes[0].sendrawtransaction(tx_hex, True) chain_txids.append(txid) @@ -185,7 +185,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # child fees - 40 BTC - so this attempt is rejected. dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] - dbl_tx.vout = [CTxOut(initial_nValue - 30*COIN, CScript([1]))] + dbl_tx.vout = [CTxOut(initial_nValue - 30 * COIN, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception due to insufficient fee @@ -194,7 +194,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Accepted with sufficient fee dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] - dbl_tx.vout = [CTxOut(1*COIN, CScript([1]))] + dbl_tx.vout = [CTxOut(1 * COIN, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) self.nodes[0].sendrawtransaction(dbl_tx_hex, True) @@ -247,7 +247,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Attempt double-spend, will fail because too little fee paid dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] - dbl_tx.vout = [CTxOut(initial_nValue - fee*n, CScript([1]))] + dbl_tx.vout = [CTxOut(initial_nValue - fee * n, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception due to insufficient fee assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True) @@ -255,7 +255,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # 1 BTC fee is enough dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] - dbl_tx.vout = [CTxOut(initial_nValue - fee*n - 1*COIN, CScript([1]))] + dbl_tx.vout = [CTxOut(initial_nValue - fee * n - 1 * COIN, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) self.nodes[0].sendrawtransaction(dbl_tx_hex, True) @@ -275,7 +275,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): dbl_tx = CTransaction() dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)] - dbl_tx.vout = [CTxOut(initial_nValue - 2*fee*n, CScript([1]))] + dbl_tx.vout = [CTxOut(initial_nValue - 2 * fee * n, CScript([1] * 35))] dbl_tx_hex = txToHex(dbl_tx) # This will raise an exception assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, True) @@ -290,7 +290,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a = CTransaction() tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) self.nodes[0].sendrawtransaction(tx1a_hex, True) @@ -311,7 +311,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a = CTransaction() tx1a.vin = [CTxIn(utxo1, nSequence=0)] - tx1a.vout = [CTxOut(int(1.1*COIN), CScript([b'a']))] + tx1a.vout = [CTxOut(int(1.1 * COIN), CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) @@ -330,7 +330,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Spend tx1a's output to test the indirect case. tx1b = CTransaction() tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)] - tx1b.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1b.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1b_hex = txToHex(tx1b) tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True) tx1b_txid = int(tx1b_txid, 16) @@ -351,7 +351,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1 = CTransaction() tx1.vin = [CTxIn(confirmed_utxo)] - tx1.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1_hex = txToHex(tx1) self.nodes[0].sendrawtransaction(tx1_hex, True) @@ -390,7 +390,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): for i in range(MAX_REPLACEMENT_LIMIT+1): tx_i = CTransaction() tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)] - tx_i.vout = [CTxOut(split_value-fee, CScript([b'a']))] + tx_i.vout = [CTxOut(split_value - fee, CScript([b'a' * 35]))] tx_i_hex = txToHex(tx_i) self.nodes[0].sendrawtransaction(tx_i_hex, True) @@ -423,14 +423,14 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Create a non-opting in transaction tx1a = CTransaction() tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)] - tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) # Shouldn't be able to double-spend tx1b = CTransaction() tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))] + tx1b.vout = [CTxOut(int(0.9 * COIN), CScript([b'b' * 35]))] tx1b_hex = txToHex(tx1b) # This will raise an exception @@ -441,14 +441,14 @@ class ReplaceByFeeTest(BitcoinTestFramework): # Create a different non-opting in transaction tx2a = CTransaction() tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)] - tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx2a_hex = txToHex(tx2a) tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True) # Still shouldn't be able to double-spend tx2b = CTransaction() tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)] - tx2b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))] + tx2b.vout = [CTxOut(int(0.9 * COIN), CScript([b'b' * 35]))] tx2b_hex = txToHex(tx2b) # This will raise an exception @@ -471,12 +471,12 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx3b = CTransaction() tx3b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)] - tx3b.vout = [CTxOut(int(0.5*COIN), CScript([b'e']))] + tx3b.vout = [CTxOut(int(0.5 * COIN), CScript([b'e' * 35]))] tx3b_hex = txToHex(tx3b) tx3c = CTransaction() tx3c.vin = [CTxIn(COutPoint(tx2a_txid, 0), nSequence=0)] - tx3c.vout = [CTxOut(int(0.5*COIN), CScript([b'f']))] + tx3c.vout = [CTxOut(int(0.5 * COIN), CScript([b'f' * 35]))] tx3c_hex = txToHex(tx3c) self.nodes[0].sendrawtransaction(tx3b_hex, True) @@ -493,7 +493,7 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx1a = CTransaction() tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)] - tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx1a_hex = txToHex(tx1a) tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True) @@ -519,14 +519,14 @@ class ReplaceByFeeTest(BitcoinTestFramework): tx2a = CTransaction() tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0)] - tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))] + tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))] tx2a_hex = txToHex(tx2a) self.nodes[0].sendrawtransaction(tx2a_hex, True) # Lower fee, but we'll prioritise it tx2b = CTransaction() tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)] - tx2b.vout = [CTxOut(int(1.01*COIN), CScript([b'a']))] + tx2b.vout = [CTxOut(int(1.01 * COIN), CScript([b'a' * 35]))] tx2b.rehash() tx2b_hex = txToHex(tx2b) |