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+#!/usr/bin/env python3
+# Copyright (c) 2014-2017 The Bitcoin Core developers
+# Distributed under the MIT software license, see the accompanying
+# file COPYING or http://www.opensource.org/licenses/mit-license.php.
+"""Test fee estimation code."""
+from decimal import Decimal
+import random
+
+from test_framework.mininode import CTransaction, CTxIn, CTxOut, COutPoint, ToHex, COIN
+from test_framework.script import CScript, OP_1, OP_DROP, OP_2, OP_HASH160, OP_EQUAL, hash160, OP_TRUE
+from test_framework.test_framework import BitcoinTestFramework
+from test_framework.util import (
+ assert_equal,
+ assert_greater_than,
+ assert_greater_than_or_equal,
+ connect_nodes,
+ satoshi_round,
+ sync_blocks,
+ sync_mempools,
+)
+
+# Construct 2 trivial P2SH's and the ScriptSigs that spend them
+# So we can create many transactions without needing to spend
+# time signing.
+REDEEM_SCRIPT_1 = CScript([OP_1, OP_DROP])
+REDEEM_SCRIPT_2 = CScript([OP_2, OP_DROP])
+P2SH_1 = CScript([OP_HASH160, hash160(REDEEM_SCRIPT_1), OP_EQUAL])
+P2SH_2 = CScript([OP_HASH160, hash160(REDEEM_SCRIPT_2), OP_EQUAL])
+
+# Associated ScriptSig's to spend satisfy P2SH_1 and P2SH_2
+SCRIPT_SIG = [CScript([OP_TRUE, REDEEM_SCRIPT_1]), CScript([OP_TRUE, REDEEM_SCRIPT_2])]
+
+def small_txpuzzle_randfee(from_node, conflist, unconflist, amount, min_fee, fee_increment):
+ """Create and send a transaction with a random fee.
+
+ The transaction pays to a trivial P2SH script, and assumes that its inputs
+ are of the same form.
+ The function takes a list of confirmed outputs and unconfirmed outputs
+ and attempts to use the confirmed list first for its inputs.
+ It adds the newly created outputs to the unconfirmed list.
+ Returns (raw transaction, fee)."""
+
+ # It's best to exponentially distribute our random fees
+ # because the buckets are exponentially spaced.
+ # Exponentially distributed from 1-128 * fee_increment
+ rand_fee = float(fee_increment) * (1.1892 ** random.randint(0, 28))
+ # Total fee ranges from min_fee to min_fee + 127*fee_increment
+ fee = min_fee - fee_increment + satoshi_round(rand_fee)
+ tx = CTransaction()
+ total_in = Decimal("0.00000000")
+ while total_in <= (amount + fee) and len(conflist) > 0:
+ t = conflist.pop(0)
+ total_in += t["amount"]
+ tx.vin.append(CTxIn(COutPoint(int(t["txid"], 16), t["vout"]), b""))
+ if total_in <= amount + fee:
+ while total_in <= (amount + fee) and len(unconflist) > 0:
+ t = unconflist.pop(0)
+ total_in += t["amount"]
+ tx.vin.append(CTxIn(COutPoint(int(t["txid"], 16), t["vout"]), b""))
+ if total_in <= amount + fee:
+ raise RuntimeError("Insufficient funds: need %d, have %d" % (amount + fee, total_in))
+ tx.vout.append(CTxOut(int((total_in - amount - fee) * COIN), P2SH_1))
+ tx.vout.append(CTxOut(int(amount * COIN), P2SH_2))
+ # These transactions don't need to be signed, but we still have to insert
+ # the ScriptSig that will satisfy the ScriptPubKey.
+ for inp in tx.vin:
+ inp.scriptSig = SCRIPT_SIG[inp.prevout.n]
+ txid = from_node.sendrawtransaction(ToHex(tx), True)
+ unconflist.append({"txid": txid, "vout": 0, "amount": total_in - amount - fee})
+ unconflist.append({"txid": txid, "vout": 1, "amount": amount})
+
+ return (ToHex(tx), fee)
+
+def split_inputs(from_node, txins, txouts, initial_split=False):
+ """Generate a lot of inputs so we can generate a ton of transactions.
+
+ This function takes an input from txins, and creates and sends a transaction
+ which splits the value into 2 outputs which are appended to txouts.
+ Previously this was designed to be small inputs so they wouldn't have
+ a high coin age when the notion of priority still existed."""
+
+ prevtxout = txins.pop()
+ tx = CTransaction()
+ tx.vin.append(CTxIn(COutPoint(int(prevtxout["txid"], 16), prevtxout["vout"]), b""))
+
+ half_change = satoshi_round(prevtxout["amount"] / 2)
+ rem_change = prevtxout["amount"] - half_change - Decimal("0.00001000")
+ tx.vout.append(CTxOut(int(half_change * COIN), P2SH_1))
+ tx.vout.append(CTxOut(int(rem_change * COIN), P2SH_2))
+
+ # If this is the initial split we actually need to sign the transaction
+ # Otherwise we just need to insert the proper ScriptSig
+ if (initial_split):
+ completetx = from_node.signrawtransactionwithwallet(ToHex(tx))["hex"]
+ else:
+ tx.vin[0].scriptSig = SCRIPT_SIG[prevtxout["vout"]]
+ completetx = ToHex(tx)
+ txid = from_node.sendrawtransaction(completetx, True)
+ txouts.append({"txid": txid, "vout": 0, "amount": half_change})
+ txouts.append({"txid": txid, "vout": 1, "amount": rem_change})
+
+def check_estimates(node, fees_seen, max_invalid):
+ """Call estimatesmartfee and verify that the estimates meet certain invariants."""
+
+ delta = 1.0e-6 # account for rounding error
+ last_feerate = float(max(fees_seen))
+ all_smart_estimates = [node.estimatesmartfee(i) for i in range(1, 26)]
+ for i, e in enumerate(all_smart_estimates): # estimate is for i+1
+ feerate = float(e["feerate"])
+ assert_greater_than(feerate, 0)
+
+ if feerate + delta < min(fees_seen) or feerate - delta > max(fees_seen):
+ raise AssertionError("Estimated fee (%f) out of range (%f,%f)"
+ % (feerate, min(fees_seen), max(fees_seen)))
+ if feerate - delta > last_feerate:
+ raise AssertionError("Estimated fee (%f) larger than last fee (%f) for lower number of confirms"
+ % (feerate, last_feerate))
+ last_feerate = feerate
+
+ if i == 0:
+ assert_equal(e["blocks"], 2)
+ else:
+ assert_greater_than_or_equal(i + 1, e["blocks"])
+
+class EstimateFeeTest(BitcoinTestFramework):
+ def set_test_params(self):
+ self.num_nodes = 3
+
+ def setup_network(self):
+ """
+ We'll setup the network to have 3 nodes that all mine with different parameters.
+ But first we need to use one node to create a lot of outputs
+ which we will use to generate our transactions.
+ """
+ self.add_nodes(3, extra_args=[["-maxorphantx=1000", "-whitelist=127.0.0.1"],
+ ["-blockmaxsize=17000", "-maxorphantx=1000"],
+ ["-blockmaxsize=8000", "-maxorphantx=1000"]])
+ # Use node0 to mine blocks for input splitting
+ # Node1 mines small blocks but that are bigger than the expected transaction rate.
+ # NOTE: the CreateNewBlock code starts counting block size at 1,000 bytes,
+ # (17k is room enough for 110 or so transactions)
+ # Node2 is a stingy miner, that
+ # produces too small blocks (room for only 55 or so transactions)
+
+ def transact_and_mine(self, numblocks, mining_node):
+ min_fee = Decimal("0.00001")
+ # We will now mine numblocks blocks generating on average 100 transactions between each block
+ # We shuffle our confirmed txout set before each set of transactions
+ # small_txpuzzle_randfee will use the transactions that have inputs already in the chain when possible
+ # resorting to tx's that depend on the mempool when those run out
+ for i in range(numblocks):
+ random.shuffle(self.confutxo)
+ for j in range(random.randrange(100 - 50, 100 + 50)):
+ from_index = random.randint(1, 2)
+ (txhex, fee) = small_txpuzzle_randfee(self.nodes[from_index], self.confutxo,
+ self.memutxo, Decimal("0.005"), min_fee, min_fee)
+ tx_kbytes = (len(txhex) // 2) / 1000.0
+ self.fees_per_kb.append(float(fee) / tx_kbytes)
+ sync_mempools(self.nodes[0:3], wait=.1)
+ mined = mining_node.getblock(mining_node.generate(1)[0], True)["tx"]
+ sync_blocks(self.nodes[0:3], wait=.1)
+ # update which txouts are confirmed
+ newmem = []
+ for utx in self.memutxo:
+ if utx["txid"] in mined:
+ self.confutxo.append(utx)
+ else:
+ newmem.append(utx)
+ self.memutxo = newmem
+
+ def run_test(self):
+ self.log.info("This test is time consuming, please be patient")
+ self.log.info("Splitting inputs so we can generate tx's")
+
+ # Start node0
+ self.start_node(0)
+ self.txouts = []
+ self.txouts2 = []
+ # Split a coinbase into two transaction puzzle outputs
+ split_inputs(self.nodes[0], self.nodes[0].listunspent(0), self.txouts, True)
+
+ # Mine
+ while (len(self.nodes[0].getrawmempool()) > 0):
+ self.nodes[0].generate(1)
+
+ # Repeatedly split those 2 outputs, doubling twice for each rep
+ # Use txouts to monitor the available utxo, since these won't be tracked in wallet
+ reps = 0
+ while (reps < 5):
+ # Double txouts to txouts2
+ while (len(self.txouts) > 0):
+ split_inputs(self.nodes[0], self.txouts, self.txouts2)
+ while (len(self.nodes[0].getrawmempool()) > 0):
+ self.nodes[0].generate(1)
+ # Double txouts2 to txouts
+ while (len(self.txouts2) > 0):
+ split_inputs(self.nodes[0], self.txouts2, self.txouts)
+ while (len(self.nodes[0].getrawmempool()) > 0):
+ self.nodes[0].generate(1)
+ reps += 1
+ self.log.info("Finished splitting")
+
+ # Now we can connect the other nodes, didn't want to connect them earlier
+ # so the estimates would not be affected by the splitting transactions
+ self.start_node(1)
+ self.start_node(2)
+ connect_nodes(self.nodes[1], 0)
+ connect_nodes(self.nodes[0], 2)
+ connect_nodes(self.nodes[2], 1)
+
+ self.sync_all()
+
+ self.fees_per_kb = []
+ self.memutxo = []
+ self.confutxo = self.txouts # Start with the set of confirmed txouts after splitting
+ self.log.info("Will output estimates for 1/2/3/6/15/25 blocks")
+
+ for i in range(2):
+ self.log.info("Creating transactions and mining them with a block size that can't keep up")
+ # Create transactions and mine 10 small blocks with node 2, but create txs faster than we can mine
+ self.transact_and_mine(10, self.nodes[2])
+ check_estimates(self.nodes[1], self.fees_per_kb, 14)
+
+ self.log.info("Creating transactions and mining them at a block size that is just big enough")
+ # Generate transactions while mining 10 more blocks, this time with node1
+ # which mines blocks with capacity just above the rate that transactions are being created
+ self.transact_and_mine(10, self.nodes[1])
+ check_estimates(self.nodes[1], self.fees_per_kb, 2)
+
+ # Finish by mining a normal-sized block:
+ while len(self.nodes[1].getrawmempool()) > 0:
+ self.nodes[1].generate(1)
+
+ sync_blocks(self.nodes[0:3], wait=.1)
+ self.log.info("Final estimates after emptying mempools")
+ check_estimates(self.nodes[1], self.fees_per_kb, 2)
+
+if __name__ == '__main__':
+ EstimateFeeTest().main()