diff options
Diffstat (limited to 'src/script/standard.cpp')
| -rw-r--r-- | src/script/standard.cpp | 8 |
1 files changed, 4 insertions, 4 deletions
diff --git a/src/script/standard.cpp b/src/script/standard.cpp index 5d80891485..b3f6a1b669 100644 --- a/src/script/standard.cpp +++ b/src/script/standard.cpp @@ -375,9 +375,9 @@ bool IsValidDestination(const CTxDestination& dest) { } /* Lexicographically sort a and b's hash, and compute parent hash. */ if (a.hash < b.hash) { - ret.hash = (CHashWriter(HASHER_TAPBRANCH) << a.hash << b.hash).GetSHA256(); + ret.hash = (HashWriter{HASHER_TAPBRANCH} << a.hash << b.hash).GetSHA256(); } else { - ret.hash = (CHashWriter(HASHER_TAPBRANCH) << b.hash << a.hash).GetSHA256(); + ret.hash = (HashWriter{HASHER_TAPBRANCH} << b.hash << a.hash).GetSHA256(); } return ret; } @@ -452,7 +452,7 @@ TaprootBuilder& TaprootBuilder::Add(int depth, const CScript& script, int leaf_v if (!IsValid()) return *this; /* Construct NodeInfo object with leaf hash and (if track is true) also leaf information. */ NodeInfo node; - node.hash = (CHashWriter{HASHER_TAPLEAF} << uint8_t(leaf_version) << script).GetSHA256(); + node.hash = (HashWriter{HASHER_TAPLEAF} << uint8_t(leaf_version) << script).GetSHA256(); if (track) node.leaves.emplace_back(LeafInfo{script, leaf_version, {}}); /* Insert into the branch. */ Insert(std::move(node), depth); @@ -610,7 +610,7 @@ std::optional<std::vector<std::tuple<int, CScript, int>>> InferTaprootTree(const node.done = true; stack.pop_back(); } else if (node.sub[0]->done && !node.sub[1]->done && !node.sub[1]->explored && !node.sub[1]->hash.IsNull() && - (CHashWriter{HASHER_TAPBRANCH} << node.sub[1]->hash << node.sub[1]->hash).GetSHA256() == node.hash) { + (HashWriter{HASHER_TAPBRANCH} << node.sub[1]->hash << node.sub[1]->hash).GetSHA256() == node.hash) { // Whenever there are nodes with two identical subtrees under it, we run into a problem: // the control blocks for the leaves underneath those will be identical as well, and thus // they will all be matched to the same path in the tree. The result is that at the location |