[tests] Rename feature_* functional tests.

1 files changed, 0 insertions, 565 deletions

diff --git a/test/functional/replace-by-fee.py b/test/functional/replace-by-fee.py
deleted file mode 100755
index 6b7ab0f43e..0000000000
--- a/test/functional/replace-by-fee.py
+++ /dev/null
@@ -1,565 +0,0 @@
-#!/usr/bin/env python3
-# Copyright (c) 2014-2017 The Bitcoin Core developers
-# Distributed under the MIT software license, see the accompanying
-# file COPYING or http://www.opensource.org/licenses/mit-license.php.
-"""Test the RBF code."""
-
-from test_framework.test_framework import BitcoinTestFramework
-from test_framework.util import *
-from test_framework.script import *
-from test_framework.mininode import *
-
-MAX_REPLACEMENT_LIMIT = 100
-
-def txToHex(tx):
-    return bytes_to_hex_str(tx.serialize())
-
-def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])):
-    """Create a txout with a given amount and scriptPubKey
-
-    Mines coins as needed.
-
-    confirmed - txouts created will be confirmed in the blockchain;
-                unconfirmed otherwise.
-    """
-    fee = 1*COIN
-    while node.getbalance() < satoshi_round((amount + fee)/COIN):
-        node.generate(100)
-
-    new_addr = node.getnewaddress()
-    txid = node.sendtoaddress(new_addr, satoshi_round((amount+fee)/COIN))
-    tx1 = node.getrawtransaction(txid, 1)
-    txid = int(txid, 16)
-    i = None
-
-    for i, txout in enumerate(tx1['vout']):
-        if txout['scriptPubKey']['addresses'] == [new_addr]:
-            break
-    assert i is not None
-
-    tx2 = CTransaction()
-    tx2.vin = [CTxIn(COutPoint(txid, i))]
-    tx2.vout = [CTxOut(amount, scriptPubKey)]
-    tx2.rehash()
-
-    signed_tx = node.signrawtransaction(txToHex(tx2))
-
-    txid = node.sendrawtransaction(signed_tx['hex'], True)
-
-    # If requested, ensure txouts are confirmed.
-    if confirmed:
-        mempool_size = len(node.getrawmempool())
-        while mempool_size > 0:
-            node.generate(1)
-            new_size = len(node.getrawmempool())
-            # Error out if we have something stuck in the mempool, as this
-            # would likely be a bug.
-            assert(new_size < mempool_size)
-            mempool_size = new_size
-
-    return COutPoint(int(txid, 16), 0)
-
-class ReplaceByFeeTest(BitcoinTestFramework):
-
-    def set_test_params(self):
-        self.num_nodes = 2
-        self.extra_args= [["-maxorphantx=1000",
-                           "-whitelist=127.0.0.1",
-                           "-limitancestorcount=50",
-                           "-limitancestorsize=101",
-                           "-limitdescendantcount=200",
-                           "-limitdescendantsize=101"],
-                           ["-mempoolreplacement=0"]]
-
-    def run_test(self):
-        # Leave IBD
-        self.nodes[0].generate(1)
-
-        make_utxo(self.nodes[0], 1*COIN)
-
-        # Ensure nodes are synced
-        self.sync_all()
-
-        self.log.info("Running test simple doublespend...")
-        self.test_simple_doublespend()
-
-        self.log.info("Running test doublespend chain...")
-        self.test_doublespend_chain()
-
-        self.log.info("Running test doublespend tree...")
-        self.test_doublespend_tree()
-
-        self.log.info("Running test replacement feeperkb...")
-        self.test_replacement_feeperkb()
-
-        self.log.info("Running test spends of conflicting outputs...")
-        self.test_spends_of_conflicting_outputs()
-
-        self.log.info("Running test new unconfirmed inputs...")
-        self.test_new_unconfirmed_inputs()
-
-        self.log.info("Running test too many replacements...")
-        self.test_too_many_replacements()
-
-        self.log.info("Running test opt-in...")
-        self.test_opt_in()
-
-        self.log.info("Running test RPC...")
-        self.test_rpc()
-
-        self.log.info("Running test prioritised transactions...")
-        self.test_prioritised_transactions()
-
-        self.log.info("Passed")
-
-    def test_simple_doublespend(self):
-        """Simple doublespend"""
-        tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        # make_utxo may have generated a bunch of blocks, so we need to sync
-        # before we can spend the coins generated, or else the resulting
-        # transactions might not be accepted by our peers.
-        self.sync_all()
-
-        tx1a = CTransaction()
-        tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1a_hex = txToHex(tx1a)
-        tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
-
-        self.sync_all()
-
-        # Should fail because we haven't changed the fee
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1b.vout = [CTxOut(1*COIN, CScript([b'b']))]
-        tx1b_hex = txToHex(tx1b)
-
-        # This will raise an exception due to insufficient fee
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
-        # This will raise an exception due to transaction replacement being disabled
-        assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True)
-
-        # Extra 0.1 BTC fee
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
-        tx1b_hex = txToHex(tx1b)
-        # Replacement still disabled even with "enough fee"
-        assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True)
-        # Works when enabled
-        tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
-
-        mempool = self.nodes[0].getrawmempool()
-
-        assert (tx1a_txid not in mempool)
-        assert (tx1b_txid in mempool)
-
-        assert_equal(tx1b_hex, self.nodes[0].getrawtransaction(tx1b_txid))
-
-        # Second node is running mempoolreplacement=0, will not replace originally-seen txn
-        mempool = self.nodes[1].getrawmempool()
-        assert tx1a_txid in mempool
-        assert tx1b_txid not in mempool
-
-    def test_doublespend_chain(self):
-        """Doublespend of a long chain"""
-
-        initial_nValue = 50*COIN
-        tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
-
-        prevout = tx0_outpoint
-        remaining_value = initial_nValue
-        chain_txids = []
-        while remaining_value > 10*COIN:
-            remaining_value -= 1*COIN
-            tx = CTransaction()
-            tx.vin = [CTxIn(prevout, nSequence=0)]
-            tx.vout = [CTxOut(remaining_value, CScript([1]))]
-            tx_hex = txToHex(tx)
-            txid = self.nodes[0].sendrawtransaction(tx_hex, True)
-            chain_txids.append(txid)
-            prevout = COutPoint(int(txid, 16), 0)
-
-        # Whether the double-spend is allowed is evaluated by including all
-        # child fees - 40 BTC - so this attempt is rejected.
-        dbl_tx = CTransaction()
-        dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        dbl_tx.vout = [CTxOut(initial_nValue - 30*COIN, CScript([1]))]
-        dbl_tx_hex = txToHex(dbl_tx)
-
-        # This will raise an exception due to insufficient fee
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
-
-        # Accepted with sufficient fee
-        dbl_tx = CTransaction()
-        dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        dbl_tx.vout = [CTxOut(1*COIN, CScript([1]))]
-        dbl_tx_hex = txToHex(dbl_tx)
-        self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
-
-        mempool = self.nodes[0].getrawmempool()
-        for doublespent_txid in chain_txids:
-            assert(doublespent_txid not in mempool)
-
-    def test_doublespend_tree(self):
-        """Doublespend of a big tree of transactions"""
-
-        initial_nValue = 50*COIN
-        tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
-
-        def branch(prevout, initial_value, max_txs, tree_width=5, fee=0.0001*COIN, _total_txs=None):
-            if _total_txs is None:
-                _total_txs = [0]
-            if _total_txs[0] >= max_txs:
-                return
-
-            txout_value = (initial_value - fee) // tree_width
-            if txout_value < fee:
-                return
-
-            vout = [CTxOut(txout_value, CScript([i+1]))
-                    for i in range(tree_width)]
-            tx = CTransaction()
-            tx.vin = [CTxIn(prevout, nSequence=0)]
-            tx.vout = vout
-            tx_hex = txToHex(tx)
-
-            assert(len(tx.serialize()) < 100000)
-            txid = self.nodes[0].sendrawtransaction(tx_hex, True)
-            yield tx
-            _total_txs[0] += 1
-
-            txid = int(txid, 16)
-
-            for i, txout in enumerate(tx.vout):
-                for x in branch(COutPoint(txid, i), txout_value,
-                                  max_txs,
-                                  tree_width=tree_width, fee=fee,
-                                  _total_txs=_total_txs):
-                    yield x
-
-        fee = int(0.0001*COIN)
-        n = MAX_REPLACEMENT_LIMIT
-        tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
-        assert_equal(len(tree_txs), n)
-
-        # Attempt double-spend, will fail because too little fee paid
-        dbl_tx = CTransaction()
-        dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        dbl_tx.vout = [CTxOut(initial_nValue - fee*n, CScript([1]))]
-        dbl_tx_hex = txToHex(dbl_tx)
-        # This will raise an exception due to insufficient fee
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
-
-        # 1 BTC fee is enough
-        dbl_tx = CTransaction()
-        dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        dbl_tx.vout = [CTxOut(initial_nValue - fee*n - 1*COIN, CScript([1]))]
-        dbl_tx_hex = txToHex(dbl_tx)
-        self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
-
-        mempool = self.nodes[0].getrawmempool()
-
-        for tx in tree_txs:
-            tx.rehash()
-            assert (tx.hash not in mempool)
-
-        # Try again, but with more total transactions than the "max txs
-        # double-spent at once" anti-DoS limit.
-        for n in (MAX_REPLACEMENT_LIMIT+1, MAX_REPLACEMENT_LIMIT*2):
-            fee = int(0.0001*COIN)
-            tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
-            tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
-            assert_equal(len(tree_txs), n)
-
-            dbl_tx = CTransaction()
-            dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-            dbl_tx.vout = [CTxOut(initial_nValue - 2*fee*n, CScript([1]))]
-            dbl_tx_hex = txToHex(dbl_tx)
-            # This will raise an exception
-            assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
-
-            for tx in tree_txs:
-                tx.rehash()
-                self.nodes[0].getrawtransaction(tx.hash)
-
-    def test_replacement_feeperkb(self):
-        """Replacement requires fee-per-KB to be higher"""
-        tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        tx1a = CTransaction()
-        tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1a_hex = txToHex(tx1a)
-        self.nodes[0].sendrawtransaction(tx1a_hex, True)
-
-        # Higher fee, but the fee per KB is much lower, so the replacement is
-        # rejected.
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1b.vout = [CTxOut(int(0.001*COIN), CScript([b'a'*999000]))]
-        tx1b_hex = txToHex(tx1b)
-
-        # This will raise an exception due to insufficient fee
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
-
-    def test_spends_of_conflicting_outputs(self):
-        """Replacements that spend conflicting tx outputs are rejected"""
-        utxo1 = make_utxo(self.nodes[0], int(1.2*COIN))
-        utxo2 = make_utxo(self.nodes[0], 3*COIN)
-
-        tx1a = CTransaction()
-        tx1a.vin = [CTxIn(utxo1, nSequence=0)]
-        tx1a.vout = [CTxOut(int(1.1*COIN), CScript([b'a']))]
-        tx1a_hex = txToHex(tx1a)
-        tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
-
-        tx1a_txid = int(tx1a_txid, 16)
-
-        # Direct spend an output of the transaction we're replacing.
-        tx2 = CTransaction()
-        tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0)]
-        tx2.vin.append(CTxIn(COutPoint(tx1a_txid, 0), nSequence=0))
-        tx2.vout = tx1a.vout
-        tx2_hex = txToHex(tx2)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True)
-
-        # Spend tx1a's output to test the indirect case.
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
-        tx1b.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1b_hex = txToHex(tx1b)
-        tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
-        tx1b_txid = int(tx1b_txid, 16)
-
-        tx2 = CTransaction()
-        tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0),
-                   CTxIn(COutPoint(tx1b_txid, 0))]
-        tx2.vout = tx1a.vout
-        tx2_hex = txToHex(tx2)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True)
-
-    def test_new_unconfirmed_inputs(self):
-        """Replacements that add new unconfirmed inputs are rejected"""
-        confirmed_utxo = make_utxo(self.nodes[0], int(1.1*COIN))
-        unconfirmed_utxo = make_utxo(self.nodes[0], int(0.1*COIN), False)
-
-        tx1 = CTransaction()
-        tx1.vin = [CTxIn(confirmed_utxo)]
-        tx1.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1_hex = txToHex(tx1)
-        self.nodes[0].sendrawtransaction(tx1_hex, True)
-
-        tx2 = CTransaction()
-        tx2.vin = [CTxIn(confirmed_utxo), CTxIn(unconfirmed_utxo)]
-        tx2.vout = tx1.vout
-        tx2_hex = txToHex(tx2)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, True)
-
-    def test_too_many_replacements(self):
-        """Replacements that evict too many transactions are rejected"""
-        # Try directly replacing more than MAX_REPLACEMENT_LIMIT
-        # transactions
-
-        # Start by creating a single transaction with many outputs
-        initial_nValue = 10*COIN
-        utxo = make_utxo(self.nodes[0], initial_nValue)
-        fee = int(0.0001*COIN)
-        split_value = int((initial_nValue-fee)/(MAX_REPLACEMENT_LIMIT+1))
-
-        outputs = []
-        for i in range(MAX_REPLACEMENT_LIMIT+1):
-            outputs.append(CTxOut(split_value, CScript([1])))
-
-        splitting_tx = CTransaction()
-        splitting_tx.vin = [CTxIn(utxo, nSequence=0)]
-        splitting_tx.vout = outputs
-        splitting_tx_hex = txToHex(splitting_tx)
-
-        txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, True)
-        txid = int(txid, 16)
-
-        # Now spend each of those outputs individually
-        for i in range(MAX_REPLACEMENT_LIMIT+1):
-            tx_i = CTransaction()
-            tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)]
-            tx_i.vout = [CTxOut(split_value-fee, CScript([b'a']))]
-            tx_i_hex = txToHex(tx_i)
-            self.nodes[0].sendrawtransaction(tx_i_hex, True)
-
-        # Now create doublespend of the whole lot; should fail.
-        # Need a big enough fee to cover all spending transactions and have
-        # a higher fee rate
-        double_spend_value = (split_value-100*fee)*(MAX_REPLACEMENT_LIMIT+1)
-        inputs = []
-        for i in range(MAX_REPLACEMENT_LIMIT+1):
-            inputs.append(CTxIn(COutPoint(txid, i), nSequence=0))
-        double_tx = CTransaction()
-        double_tx.vin = inputs
-        double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
-        double_tx_hex = txToHex(double_tx)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, True)
-
-        # If we remove an input, it should pass
-        double_tx = CTransaction()
-        double_tx.vin = inputs[0:-1]
-        double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
-        double_tx_hex = txToHex(double_tx)
-        self.nodes[0].sendrawtransaction(double_tx_hex, True)
-
-    def test_opt_in(self):
-        """Replacing should only work if orig tx opted in"""
-        tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        # Create a non-opting in transaction
-        tx1a = CTransaction()
-        tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)]
-        tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1a_hex = txToHex(tx1a)
-        tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
-
-        # Shouldn't be able to double-spend
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
-        tx1b_hex = txToHex(tx1b)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, True)
-
-        tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        # Create a different non-opting in transaction
-        tx2a = CTransaction()
-        tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)]
-        tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx2a_hex = txToHex(tx2a)
-        tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True)
-
-        # Still shouldn't be able to double-spend
-        tx2b = CTransaction()
-        tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
-        tx2b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
-        tx2b_hex = txToHex(tx2b)
-
-        # This will raise an exception
-        assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, True)
-
-        # Now create a new transaction that spends from tx1a and tx2a
-        # opt-in on one of the inputs
-        # Transaction should be replaceable on either input
-
-        tx1a_txid = int(tx1a_txid, 16)
-        tx2a_txid = int(tx2a_txid, 16)
-
-        tx3a = CTransaction()
-        tx3a.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0xffffffff),
-                    CTxIn(COutPoint(tx2a_txid, 0), nSequence=0xfffffffd)]
-        tx3a.vout = [CTxOut(int(0.9*COIN), CScript([b'c'])), CTxOut(int(0.9*COIN), CScript([b'd']))]
-        tx3a_hex = txToHex(tx3a)
-
-        self.nodes[0].sendrawtransaction(tx3a_hex, True)
-
-        tx3b = CTransaction()
-        tx3b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
-        tx3b.vout = [CTxOut(int(0.5*COIN), CScript([b'e']))]
-        tx3b_hex = txToHex(tx3b)
-
-        tx3c = CTransaction()
-        tx3c.vin = [CTxIn(COutPoint(tx2a_txid, 0), nSequence=0)]
-        tx3c.vout = [CTxOut(int(0.5*COIN), CScript([b'f']))]
-        tx3c_hex = txToHex(tx3c)
-
-        self.nodes[0].sendrawtransaction(tx3b_hex, True)
-        # If tx3b was accepted, tx3c won't look like a replacement,
-        # but make sure it is accepted anyway
-        self.nodes[0].sendrawtransaction(tx3c_hex, True)
-
-    def test_prioritised_transactions(self):
-        # Ensure that fee deltas used via prioritisetransaction are
-        # correctly used by replacement logic
-
-        # 1. Check that feeperkb uses modified fees
-        tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        tx1a = CTransaction()
-        tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx1a_hex = txToHex(tx1a)
-        tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
-
-        # Higher fee, but the actual fee per KB is much lower.
-        tx1b = CTransaction()
-        tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
-        tx1b.vout = [CTxOut(int(0.001*COIN), CScript([b'a'*740000]))]
-        tx1b_hex = txToHex(tx1b)
-
-        # Verify tx1b cannot replace tx1a.
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
-
-        # Use prioritisetransaction to set tx1a's fee to 0.
-        self.nodes[0].prioritisetransaction(txid=tx1a_txid, fee_delta=int(-0.1*COIN))
-
-        # Now tx1b should be able to replace tx1a
-        tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
-
-        assert(tx1b_txid in self.nodes[0].getrawmempool())
-
-        # 2. Check that absolute fee checks use modified fee.
-        tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
-
-        tx2a = CTransaction()
-        tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0)]
-        tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))]
-        tx2a_hex = txToHex(tx2a)
-        self.nodes[0].sendrawtransaction(tx2a_hex, True)
-
-        # Lower fee, but we'll prioritise it
-        tx2b = CTransaction()
-        tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
-        tx2b.vout = [CTxOut(int(1.01*COIN), CScript([b'a']))]
-        tx2b.rehash()
-        tx2b_hex = txToHex(tx2b)
-
-        # Verify tx2b cannot replace tx2a.
-        assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b_hex, True)
-
-        # Now prioritise tx2b to have a higher modified fee
-        self.nodes[0].prioritisetransaction(txid=tx2b.hash, fee_delta=int(0.1*COIN))
-
-        # tx2b should now be accepted
-        tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, True)
-
-        assert(tx2b_txid in self.nodes[0].getrawmempool())
-
-    def test_rpc(self):
-        us0 = self.nodes[0].listunspent()[0]
-        ins = [us0]
-        outs = {self.nodes[0].getnewaddress() : Decimal(1.0000000)}
-        rawtx0 = self.nodes[0].createrawtransaction(ins, outs, 0, True)
-        rawtx1 = self.nodes[0].createrawtransaction(ins, outs, 0, False)
-        json0  = self.nodes[0].decoderawtransaction(rawtx0)
-        json1  = self.nodes[0].decoderawtransaction(rawtx1)
-        assert_equal(json0["vin"][0]["sequence"], 4294967293)
-        assert_equal(json1["vin"][0]["sequence"], 4294967295)
-
-        rawtx2 = self.nodes[0].createrawtransaction([], outs)
-        frawtx2a = self.nodes[0].fundrawtransaction(rawtx2, {"replaceable": True})
-        frawtx2b = self.nodes[0].fundrawtransaction(rawtx2, {"replaceable": False})
-
-        json0  = self.nodes[0].decoderawtransaction(frawtx2a['hex'])
-        json1  = self.nodes[0].decoderawtransaction(frawtx2b['hex'])
-        assert_equal(json0["vin"][0]["sequence"], 4294967293)
-        assert_equal(json1["vin"][0]["sequence"], 4294967294)
-
-if __name__ == '__main__':
-    ReplaceByFeeTest().main()