Merge #14214: convert C-style (void) parameter lists to C++ style ()

3ccfa34b32 convert C-style (void) parameter lists to C++ style () (Arvid Norberg)

Pull request description:

  In C, an empty parameter list, `()`, means the function takes any arguments, and `(void)` means the function does not take any parameters.
  In C++, an empty parameter list means the function does not take any parameters.

  So, C++ still supports `(void)` parameter lists with the same semantics, why change to `()`?

  1. removing the redundant `void` improves signal-to-noise ratio of the code
  2. using `(void)` exposes a rare inconsistency in that a template taking a template `(T)` parameter list, cannot be instantiated with `T=void`

Tree-SHA512: be2897b6c5e474873aa878ed6bac098382cd21866aec33752fe40b089a6331aa6263cae749aba1b4a41e8467f1a47086d32eb74abaf09927fd5a2f44a4b2109a

1 files changed, 1 insertions, 1 deletions

diff --git a/src/test/crypto_tests.cpp b/src/test/crypto_tests.cpp
index 19521027a9..713e3e2ded 100644
--- a/src/test/crypto_tests.cpp
+++ b/src/test/crypto_tests.cpp
@@ -200,7 +200,7 @@ static void TestChaCha20(const std::string &hexkey, uint64_t nonce, uint64_t see
     BOOST_CHECK(out == outres);
 }
 
-static std::string LongTestString(void) {
+static std::string LongTestString() {
     std::string ret;
     for (int i=0; i<200000; i++) {
         ret += (unsigned char)(i);