Add RPC test for abandoned and conflicted transactions.

1 files changed, 153 insertions, 0 deletions

diff --git a/qa/rpc-tests/abandonconflict.py b/qa/rpc-tests/abandonconflict.py
new file mode 100755
index 0000000000..38028df079
--- /dev/null
+++ b/qa/rpc-tests/abandonconflict.py
@@ -0,0 +1,153 @@
+#!/usr/bin/env python2
+# Copyright (c) 2014-2015 The Bitcoin Core developers
+# Distributed under the MIT software license, see the accompanying
+# file COPYING or http://www.opensource.org/licenses/mit-license.php.
+
+
+from test_framework.test_framework import BitcoinTestFramework
+from test_framework.util import *
+try:
+    import urllib.parse as urlparse
+except ImportError:
+    import urlparse
+
+class AbandonConflictTest(BitcoinTestFramework):
+
+    def setup_network(self):
+        self.nodes = []
+        self.nodes.append(start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.00001"]))
+        self.nodes.append(start_node(1, self.options.tmpdir, ["-debug","-logtimemicros"]))
+        connect_nodes(self.nodes[0], 1)
+
+    def run_test(self):
+        self.nodes[1].generate(100)
+        sync_blocks(self.nodes)
+        balance = self.nodes[0].getbalance()
+        txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+        txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+        txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
+        sync_mempools(self.nodes)
+        self.nodes[1].generate(1)
+
+        sync_blocks(self.nodes)
+        newbalance = self.nodes[0].getbalance()
+        assert(balance - newbalance < Decimal("0.001")) #no more than fees lost
+        balance = newbalance
+
+        url = urlparse.urlparse(self.nodes[1].url)
+        self.nodes[0].disconnectnode(url.hostname+":"+str(p2p_port(1)))
+
+        # Identify the 10btc outputs
+        nA = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txA, 1)["vout"]) if vout["value"] == Decimal("10"))
+        nB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txB, 1)["vout"]) if vout["value"] == Decimal("10"))
+        nC = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txC, 1)["vout"]) if vout["value"] == Decimal("10"))
+
+        inputs =[]
+        # spend 10btc outputs from txA and txB
+        inputs.append({"txid":txA, "vout":nA})
+        inputs.append({"txid":txB, "vout":nB})
+        outputs = {}
+
+        outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998")
+        outputs[self.nodes[1].getnewaddress()] = Decimal("5")
+        signed = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs))
+        txAB1 = self.nodes[0].sendrawtransaction(signed["hex"])
+
+        # Identify the 14.99998btc output
+        nAB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txAB1, 1)["vout"]) if vout["value"] == Decimal("14.99998"))
+
+        #Create a child tx spending AB1 and C
+        inputs = []
+        inputs.append({"txid":txAB1, "vout":nAB})
+        inputs.append({"txid":txC, "vout":nC})
+        outputs = {}
+        outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996")
+        signed2 = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs))
+        txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"])
+
+        # In mempool txs from self should increase balance from change
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance - Decimal("30") + Decimal("24.9996"))
+        balance = newbalance
+
+        # Restart the node with a higher min relay fee so the parent tx is no longer in mempool
+        # TODO: redo with eviction
+        # Note had to make sure tx did not have AllowFree priority
+        stop_node(self.nodes[0],0)
+        self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.0001"])
+
+        # Verify txs no longer in mempool
+        assert(len(self.nodes[0].getrawmempool()) == 0)
+
+        # Not in mempool txs from self should only reduce balance
+        # inputs are still spent, but change not received
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance - Decimal("24.9996"))
+        balance = newbalance
+
+        # Abandon original transaction and verify inputs are available again
+        # including that the child tx was also abandoned
+        self.nodes[0].abandontransaction(txAB1)
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance + Decimal("30"))
+        balance = newbalance
+
+        # Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned
+        stop_node(self.nodes[0],0)
+        self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.00001"])
+        assert(len(self.nodes[0].getrawmempool()) == 0)
+        assert(self.nodes[0].getbalance() == balance)
+
+        # But if its received again then it is unabandoned
+        # And since now in mempool, the change is available
+        # But its child tx remains abandoned
+        self.nodes[0].sendrawtransaction(signed["hex"])
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance - Decimal("20") + Decimal("14.99998"))
+        balance = newbalance
+
+        # Send child tx again so its unabandoned
+        self.nodes[0].sendrawtransaction(signed2["hex"])
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996"))
+        balance = newbalance
+
+        # Remove using high relay fee again
+        stop_node(self.nodes[0],0)
+        self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.0001"])
+        assert(len(self.nodes[0].getrawmempool()) == 0)
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance - Decimal("24.9996"))
+        balance = newbalance
+
+        # Create a double spend of AB1 by spending again from only A's 10 output
+        # Mine double spend from node 1
+        inputs =[]
+        inputs.append({"txid":txA, "vout":nA})
+        outputs = {}
+        outputs[self.nodes[1].getnewaddress()] = Decimal("9.9999")
+        tx = self.nodes[0].createrawtransaction(inputs, outputs)
+        signed = self.nodes[0].signrawtransaction(tx)
+        self.nodes[1].sendrawtransaction(signed["hex"])
+        self.nodes[1].generate(1)
+
+        connect_nodes(self.nodes[0], 1)
+        sync_blocks(self.nodes)
+
+        # Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted
+        newbalance = self.nodes[0].getbalance()
+        assert(newbalance == balance + Decimal("20"))
+        balance = newbalance
+
+        # There is currently a minor bug around this and so this test doesn't work.  See Issue #7315
+        # Invalidate the block with the double spend and B's 10 BTC output should no longer be available
+        # Don't think C's should either
+        self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
+        newbalance = self.nodes[0].getbalance()
+        #assert(newbalance == balance - Decimal("10"))
+        print "If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer"
+        print "conflicted has not resumed causing its inputs to be seen as spent.  See Issue #7315"
+        print balance , " -> " , newbalance , " ?"
+
+if __name__ == '__main__':
+    AbandonConflictTest().main()